使用单词优先级按升序对字符串数组进行排序

Question

对于以下数组

[
  { name: '4K UHD', commentator: 'Ali' },
  { name: 'English 1 HD', commentator: 'Ahmed' },
  { name: 'English 3 HD', commentator: 'Ahmed' },
  { name: 'Premium 1 HD', commentator: 'Ali' },
  { name: 'Premium 2 HD', commentator: 'Ahmed' },
]

我想对其进行排序，以便name为Premium的对象（作为最后两个对象）排在第一位，但也按升序排列。

想要的结果是这样的

[
  { name: 'Premium 1 HD', commentator: 'Ali' },
  { name: 'Premium 2 HD', commentator: 'Ahmed' },
  { name: '4K UHD', commentator: 'Ali' },
  { name: 'English 1 HD', commentator: 'Ahmed' },
  { name: 'English 3 HD', commentator: 'Ahmed' },
]

// or like this
[
  { name: 'Premium 1 HD', commentator: 'Ali' },
  { name: 'Premium 2 HD', commentator: 'Ahmed' },
  { name: 'English 1 HD', commentator: 'Ahmed' },
  { name: 'English 3 HD', commentator: 'Ahmed' },
  { name: '4K UHD', commentator: 'Ali' },
]

Answer 1

通过创建自定义比较 function

const cmp = (a, b) => {
    const pa = a.name.startsWith("Premium");
    const pb = b.name.startsWith("Premium");
    return 
        pa !== pb 
          // comparing Premium vs non-Premium, Premium "wins"
        ? (pa ? -1 : 1) 
          // everything else (i.e. Prem vs Prem or non-Prem vs non-Prem)
        : a.name.localeCompare(b.name); 
};

dataArray.sort(cmp);

您可以确保以Premium开头的所有字符串都移到排序的顶部，同时确保在Premium和非Premium “组”之间保留排序顺序。

Answer 2

尝试降序：

array.sort((a, b) => a.name < b.name ? 1 : -1)