Go中的Rust相当于append是什么？

Question

我试图通过自己阅读文档来弄清楚，但没有运气如何将这个 Go function 转换为 Rust：

func main() {
  cards := []string{"Ace of Diamonds", newCard()}
  cards = append(cards, "Six of Spades")

  fmt.Println(cards)
}

func newCard() string {
  return "Five of Diamonds"
}

这是不正确的，至少 cards.append 我知道是错误的：

fn main() {
    let mut cards: [&str; 2] = ["Ace of Diamonds", new_card()];
    let mut additional_card: [&str; 1] = ["Six of Spades"];
    cards.append(additional_card);

    println!("cards")
}

fn new_card() -> &'static str  {
    "Five of Diamonds"
}

Answer 1

你不能。 像 Go 一样，Rust arrays 是固定大小。

类型[&str; 2] [&str; 2] in Rust 大致相当于[2]string in Go，你也不能append到。

您可以在 Rust 中获得的最接近 Go 切片的是一个Vec ，您可以像这样使用它：

fn main() {
    let mut cards = vec!["Ace of Diamonds", new_card()];
    let additional_cards: [&str; 2] = ["Six of Spades", "Seven of Clubs"];
    // for anything that implements `IntoIter` of cards
    cards.extend(additional_cards);
    // or for a single card only
    cards.push("Three of Hearts");

    println!("{cards:?}")
}

fn new_card() -> &'static str {
    "Five of Diamonds"
}