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Python 位数与平均值之和

[英]Python Sum of digits with average

大家好,我是编程新手,代码中有一个小问题,我需要求出总和的平均值,我已经对数字求和了,这里是代码:

num = int(input("Enter a number\n"))
r = 0
m = 0
while num != 0:
    m = num % 10
    r = r + m
    num = int(num / 10)
print(f"The sum of all digits is {result} and the average is")

我需要平均值,但我不知道如何得到它(例如在我添加 5555、5+5+5+5 = 20 的数字中)我如何得到平均值,谢谢

我试着做 r / m 但也没有用

这是简短的解决方案:

num = input("Enter a number\n")
s = sum([int(x) for x in num])
a = s / len(num)

print(f"The sum of all digits is {s} and the average is {a}")

此外,这是您的代码的固定版本:

num = int(input("Enter a number\n"))
r = 0
m = 0
t = 0
while num != 0:
    m = num % 10
    r = r + m
    num = int(num / 10)
    t = t + 1
print(f"The sum of all digits is {r} and the average is {r/t}")
n_str = input("Enter numbers by gaps: ") n = [float(num) for num in n_str.split()] summ = 0 for i in n: summ = summ + i print("Average of ", n, " is ", summ / len(n))

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