将字典输出打印到列表中

Question

user = int(input())


dict_nums = {
            'a' : [1,2,3,4,5,6,7,8,9],
            'b' : [11,12,13,14,15,16,17,18,19],
            'c' : [21,22,23,24,25,26,27,28,29],
            'd' : [31,32,33,34,35,36,37,38,39],
            'e' : [41,42,43,44,45,46,47,48,49],
            'f' : [51,52,53,54,55,56,57,58,59],
            'h' : [61,62,63,64,65,66,67,68,69],
            'i' : [71,72,73,74,75,76,77,78,79],
            'j' : [81,82,83,84,85,86,87,88,89],
            'k' : [91,92,93,94,95,96,97,98,99],
}

n = 5

for key in dict_nums:
    if dict_nums[key][n-1] > user:
        break
    else:
        print(dict_nums[key][n-1])

输出：

5
15
25
35
45
55

我想输出为：

[5,15,25,35,45,55]

我试过.values ， .items等，但我收到错误，例如

TypeError: 'dict_values' 对象不可订阅

和

TypeError: 'dict' 对象不可调用

ETC

Answer 1

使用list comprehension ：

print([dict_nums[k][n-1] for k in dict_nums if dict_nums[k][n-1] <= user])