类字符串类型变量的“NoneType”错误消息

Question

我知道 re.search 返回一个匹配对象re.search(pattern, string, flags=0)我正在测试匹配是否成功，然后检索字符串。

# matchTest.py --- testing match object returns

import re

# expected_pattern = suburbRegex
suburbRegex = "(?s)(,_\S+\s)"
# line leading up to and including expected_pattern
mostOfLineRex = "(?s)(^.+,\S+)"
# expected_pattern to end of line
theRestRex = "(?s),_\S+\s\w+\s(.+)"

fileLines = ['173 ANDREWS John Frances 20 Bell_Road,_Sub_urbia Semi Retired\n']

for fileLine in fileLines:
    
    result = re.search(suburbRegex, fileLine)
    # print(type(result)) # re.Match
    if(result):
        patResult = re.search(suburbRegex, fileLine).group(0)
        # print(patResult)
        # print(type(patResult)) # str
        # print(type(re.search(suburbRegex, fileLine).group(0))) # str

        start = re.search(mostOfLineRex, fileLine)
        if(start):
            start = re.search(mostOfLineRex, fileLine).group(0)
            # print(start)
            print(type(start)) # str
        end = re.search(theRestRex, fileLine)
        if(end):
            end = re.search(theRestRex, fileLine).group(0)
            # print(end)
            print(type(end)) # str
        
        newFileLine = start + ' ' + end 
    else:
        print("The listing does not have a suburb!")

# File "~\matchTest.py", line 31, in <module>
#    newFileLine = start + ' ' + end
# TypeError: can only concatenate str (not "NoneType") to str

我检查过开始和结束的类型是<class 'str'>那么为什么我会收到NoneType错误？

Answer 1

您对re.search()的返回值有错误的假设

>>> matches = re.search(r'[0-9]+', "testme 9"); matches; type(matches)
<re.Match object; span=(7, 8), match='9'>
<class 're.Match'>
>>> matches = re.search(r'[0-9]+', "testme"); matches; type(matches)
<class 'NoneType'>

这解释了您在尝试连接start " "和end时的错误。