如何停止所有代码和go回到开头

Question

我正在使用 selenium 注册游戏帐号。 而我用的是租号服务的api，但是因为用户太多，有些号码就用不到了。 我使用了 if 和 elif 方法，这样当我收到代码时，它将填充 web。

我尝试使用 start_time = time.time() 来计算状态是否超过 90 秒仍然返回 0 然后停止整个代码并从 for 循环再次运行，但是'返回'仅停止'input_phone_number'function，而不是所有功能。 这是我使用的代码：

def input_phone_number():
    while True:
        try:
            status_code = requests.get(f'https://api.viotp.com/session/getv2?requestId={request_id}&token={token}')
            code_data = status_code.json()['data']
            status = code_data['Status']
            code = code_data['Code']
            if status == 0:
                sleep(5) 
            elif status == 1:
                # Locate the element with the CSS selector '#code' and send the code as keyboard input
                driver.find_element(By.CSS_SELECTOR, '#code').send_keys(code)
                break


            if time.time() - start_time > 90:
                driver.close()
                return

这是原始代码：

for index, row in df.iterrows():
    Firstname = row['Fname']
    Lastname = row['Lname']
    Username = row['Username']
    Password = row['Password']
    
    def open_url():
        #code

    def input_information():
       #code

    def input_phone_number():
        response = requests.get(f'https://api.viotp.com/request/getv2?token={token}&serviceId=3')
        data = response.json()['data']
        number = data['phone_number']
        balance = data['balance']
        print('Phone Number:', number, '|', 'Balance:', balance)

        sleep(3)

        WebDriverWait(driver, 20).until(
            EC.presence_of_element_located((By.CSS_SELECTOR, '#phoneNumberId'))
        )
        driver.find_element(By.CSS_SELECTOR, '#phoneNumberId').send_keys(number)
        sleep(3)
        driver.find_element(By.CSS_SELECTOR, '#view_container > div > div > div.pwWryf.bxPAYd > div > div.zQJV3 > div > div.qhFLie > div > div > button > span').click()

        request_id = data['request_id']
        status = 0
        while status != 1:
            status_code = requests.get(f'https://api.viotp.com/session/getv2?requestId={request_id}&token={token}')
            code_data = status_code.json()['data']
            code = code_data['Code']
            status = code_data['Status']
            if status == 0:
                sleep(5)  # Sleep for 5 seconds before repeating the request
            elif status == 1:
                # Locate the element with the CSS selector '#code' and send the code as keyboard input
                driver.find_element(By.CSS_SELECTOR, '#code').send_keys(code)
        sleep(3)   
        driver.find_element(By.CSS_SELECTOR, '#view_container > div > div > div.pwWryf.bxPAYd > div > div.zQJV3 > div > div.qhFLie > div > div > button > span').click()

    def input_birthdate():
        #code
        
        

    open_url()
    input_information()
    input_phone_number()
    input_birthdate()

有人能帮我吗？ 非常感谢！

Answer 1

我要做的是不返回任何内容，而是返回一个字符串“continue”，在调用 input_phone_number() 之后我会检查返回值是否为“continue”，如果是，我会使用 continue to go 到for循环的下一次迭代。

def input_phone_number():
    while True:
        try:
            status_code = requests.get(f'https://api.viotp.com/session/getv2?requestId={request_id}&token={token}')
            code_data = status_code.json()['data']
            status = code_data['Status']
            code = code_data['Code']
            if status == 0:
                sleep(5) 
            elif status == 1:
                # Locate the element with the CSS selector '#code' and send the code as keyboard input
                driver.find_element(By.CSS_SELECTOR, '#code').send_keys(code)
                break


            if time.time() - start_time > 90:
                driver.close()
                return "continue"

    open_url()
    input_information()
    result = input_phone_number()
    if result == "continue":
        continue
    input_birthdate()