计算每一轮的总跑动次数，我还想要第一轮和第二轮的总和。 表结构如下

Question

**源表：- Cricket_Scores **

超过	球	跑步
1个	1个	1个
1个	2个	2个
1个	3个	4个
1个	4个	0
1个	5个	1个
1个	6个	2个
2个	1个	3个
2个	2个	1个
2个	3个	1个
2个	4个	4个
2个	5个	6个
2个	6个	0

我想要 Output 应该如下所示：-

超过	跑步
1个	10
2个	25

10 分：-（前 6 个球的总分，超过一分）和 25 分：-（前 6 个球的总分 + 第二个 6 个球）

或者

像下面这样的东西：-

超过	跑步
1个	10
2个	15

10 分：-（前 6 个球的总分，超过一分）和 15 分：-（后 6 个球的总分）

如何在 Oracle/SQL Developer 中编写查询。

Answer 1

GROUP BY the over s 和SUM runs以获得 runs-per-over：

SELECT over,
       SUM(runs) AS runs_per_over
FROM   cricket_scores
GROUP BY over

然后使用解析 function 来获取运行总计：

SELECT over,
       SUM(SUM(runs)) OVER (ORDER BY over) AS total_runs
FROM   cricket_scores
GROUP BY over

其中，对于示例数据：

CREATE TABLE cricket_scores( Over, Balls, Runs ) AS
SELECT 1, 1, 1 FROM DUAL UNION ALL
SELECT 1, 2, 2 FROM DUAL UNION ALL
SELECT 1, 3, 4 FROM DUAL UNION ALL
SELECT 1, 4, 0 FROM DUAL UNION ALL
SELECT 1, 5, 1 FROM DUAL UNION ALL
SELECT 1, 6, 2 FROM DUAL UNION ALL
SELECT 2, 1, 3 FROM DUAL UNION ALL
SELECT 2, 2, 1 FROM DUAL UNION ALL
SELECT 2, 3, 1 FROM DUAL UNION ALL
SELECT 2, 4, 4 FROM DUAL UNION ALL
SELECT 2, 5, 6 FROM DUAL UNION ALL
SELECT 2, 6, 0 FROM DUAL;

输出：

超过	TOTAL_RUNS 个
1个	10
2个	25

小提琴