如何编写一个 function 来生成带有 imap_tools 的邮箱登录名？

Question

我创建了一个登录邮箱的助手 function。

import imap_tools

def mailbox_login():
    try:
        with imap_tools.MailBoxUnencrypted(ENV["IMAP4_FQDN"]).login(
            ENV["RECEIVING_EMAIL_USER"], ENV["RECEIVING_EMAIL_PASSWORD"]
        ) as mailbox:
            print("Successfully logged into the mailbox.")
            return mailbox
    except imap_tools.MailboxLoginError as error:
        print(f"CRITICAL: Failed to login to the mailbox: {error}")

另一个function需要邮箱连接。

def email_count():
    """
    Get all emails from the mail server via IMAP
    """
    msgs = []
    mailbox = mailbox_login()
    for msg in mailbox.fetch():
        msgs.append(msg)
    return msgs

当我运行email_count()时，出现以下错误：

imaplib.IMAP4.error: command SEARCH illegal in state LOGOUT, only allowed in states SELECTED

我一离开with语句的scope，它就退出邮箱了。 离开mailbox_login()后有什么方法可以保持连接吗？

Answer 1

成功连接到 IMAP-Server 后需要 select 一个邮箱。 利用

mailbox.select()

连接后和搜索前。

Answer 2

尝试阅读上下文管理器 -与

https://docs.python.org/3/reference/compound_stmts.html#the-with-statement