[英]Unexpected Memory Leak [Valgrind]
今天我只是想检查一下valgrind是如何工作的。 所以我创建了一个简单的程序。
//leak.C
#include<iostream>
class leak
{
int *p;
public:
leak():p(new int[10]()){std::cout<<"Constructor of leak called\n";}
virtual void set()
{
for(int i=0;i<10;++i) p[i]=i*i;
}
virtual void display()
{
std::cout<<"In leak's display()\n";
for(int i=0;i<10;++i) std::cout<<p[i]<<std::endl;
}
virtual ~leak()
{
std::cout<<"Destructor of leak called\n";
delete[] p;
}
};
class exleak: public leak
{
double *r;
public:
exleak():r(new double[5]()){std::cout<<"Constructor of exleak called\n";}
void set()
{
leak::set();
for(int i=0;i<5;i++) r[i]=i*3.0;
}
void display()
{
leak::display();
std::cout<<"In exleak's display()\n";
for(int i=0;i<5;i++) std::cout<<r[i]<<std::endl;
}
~exleak()
{
std::cout<<"Destructor of exleak called\n";
delete[] r;
}
};
int main()
{
leak *x=new exleak();
x->set();
x->display();
delete x;
}
输出与预期一致。 我预计没有内存泄漏。 我编译了文件leak.C
并生成了可执行文件leak
。 但当我输入以下命令valgrind --leak-check=yes --verbose ./leak
,我很惊讶。 代码有内存泄漏。 :-o
这就是我得到的。
==9320==
==9320== HEAP SUMMARY:
==9320== in use at exit: 12 bytes in 1 blocks
==9320== total heap usage: 3 allocs, 2 frees, 92 bytes allocated
==9320==
==9320== 12 bytes in 1 blocks are definitely lost in loss record 1 of 1
==9320== at 0x40263A0: operator new(unsigned int) (vg_replace_malloc.c:214)
==9320== by 0x8048B0E: main (in /home/prasoon/leak)
==9320==
==9320== LEAK SUMMARY:
==9320== definitely lost: 12 bytes in 1 blocks
==9320== indirectly lost: 0 bytes in 0 blocks
==9320== possibly lost: 0 bytes in 0 blocks
==9320== still reachable: 0 bytes in 0 blocks
==9320== suppressed: 0 bytes in 0 blocks
==9320==
==9320== For counts of detected and suppressed errors, rerun with: -v
==9320== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 25 from 6)
代码如何泄漏内存?
definitely lost: 12 bytes in 1 blocks //WHERE?
编辑 : 事项已解决 。
我在2.6.18-164.11.1.el5内核和GCC 4.1.2的Linux上试过它,它没有给我任何泄漏
我没有看到任何代码问题
class exleak没有虚拟析构函数......
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.