[英]How to calculate elapsed time from now with Joda-Time?
我需要计算从一个特定日期到现在所经过的时间,并以与 StackOverflow 问题相同的格式显示它,即:
15s ago
2min ago
2hours ago
2days ago
25th Dec 08
您知道如何使用 Java Joda-Time库实现它吗? 是否有已经实现它的辅助方法,还是我应该自己编写算法?
要使用 JodaTime 计算经过时间,请使用Period
。 要在所需的人类表示中格式化经过的时间,请使用PeriodFormatter
,您可以通过PeriodFormatterBuilder
构建PeriodFormatterBuilder
。
这是一个启动示例:
DateTime myBirthDate = new DateTime(1978, 3, 26, 12, 35, 0, 0);
DateTime now = new DateTime();
Period period = new Period(myBirthDate, now);
PeriodFormatter formatter = new PeriodFormatterBuilder()
.appendSeconds().appendSuffix(" seconds ago\n")
.appendMinutes().appendSuffix(" minutes ago\n")
.appendHours().appendSuffix(" hours ago\n")
.appendDays().appendSuffix(" days ago\n")
.appendWeeks().appendSuffix(" weeks ago\n")
.appendMonths().appendSuffix(" months ago\n")
.appendYears().appendSuffix(" years ago\n")
.printZeroNever()
.toFormatter();
String elapsed = formatter.print(period);
System.out.println(elapsed);
这现在打印
3 seconds ago 51 minutes ago 7 hours ago 6 days ago 10 months ago 31 years ago
(咳,老,咳)你看,我也考虑了几个月和几年,并将其配置为在这些值为零时省略这些值。
我尝试了HumanTime,因为@sfussenegger 回答并使用了 JodaTime 的Period
但我发现的人类可读经过时间的最简单和最干净的方法是PrettyTime库。
下面是几个带有输入和输出的简单示例:
DateTime fiveMinutesAgo = DateTime.now().minusMinutes( 5 );
new PrettyTime().format( fiveMinutesAgo.toDate() );
// Outputs: "5 minutes ago"
DateTime birthday = new DateTime(1978, 3, 26, 12, 35, 0, 0);
new PrettyTime().format( birthday.toDate() );
// Outputs: "4 decades ago"
注意:我曾尝试使用库的更精确的功能,但它会产生一些奇怪的结果,因此请谨慎使用它并在非危及生命的项目中使用它。
J.P
有一个叫做HumanTime的小助手类,我很满意。
这是使用 mysql 时间戳来获取到现在的经过时间。 单数和复数被管理。 只显示最大时间。
注意:设置您自己的时区。
String getElapsedTime(String strMysqlTimestamp) {
DateTimeFormatter formatter = DateTimeFormat.forPattern("YYYY-MM-dd HH:mm:ss.S");
DateTime mysqlDate = formatter.parseDateTime(strMysqlTimestamp).
withZone(DateTimeZone.forID("Asia/Kuala_Lumpur"));
DateTime now = new DateTime();
Period period = new Period(mysqlDate, now);
int seconds = period.getSeconds();
int minutes = period.getMinutes();
int hours = period.getHours();
int days = period.getDays();
int weeks = period.getWeeks();
int months = period.getMonths();
int years = period.getYears();
String elapsedTime = "";
if (years != 0)
if (years == 1)
elapsedTime = years + " year ago";
else
elapsedTime = years + " years ago";
else if (months != 0)
if (months == 1)
elapsedTime = months + " month ago";
else
elapsedTime = months + " months ago";
else if (weeks != 0)
if (weeks == 1)
elapsedTime = weeks + " week ago";
else
elapsedTime = weeks + " weeks ago";
else if (days != 0)
if (days == 1)
elapsedTime = days + " day ago";
else
elapsedTime = days + " days ago";
else if (hours != 0)
if (hours == 1)
elapsedTime = hours + " hour ago";
else
elapsedTime = hours + " hours ago";
else if (minutes != 0)
if (minutes == 1)
elapsedTime = minutes + " minute ago";
else
elapsedTime = minutes + " minutes ago";
else if (seconds != 0)
if (seconds == 1)
elapsedTime = seconds + " second ago";
else
elapsedTime = seconds + " seconds ago";
return elapsedTime;
}
这是我的解决方案,使用joda time
。
private static final int SECOND_MILLIS = 1000;
private static final int MINUTE_MILLIS = 60 * SECOND_MILLIS;
private static final int HOUR_MILLIS = 60 * MINUTE_MILLIS;
private static final int DAY_MILLIS = 24 * HOUR_MILLIS;
public static String getTimeAgo(long time)
{
if(time < 1000000000000L)
{
time *= 1000;
}
long now = System.currentTimeMillis();
if(time > now || time <= 0)
{
return null;
}
final long diff = now - time;
if(diff < MINUTE_MILLIS)
{
return "just now";
}
else if(diff < 2 * MINUTE_MILLIS)
{
return "a minute ago";
}
else if(diff < 50 * MINUTE_MILLIS)
{
return diff / MINUTE_MILLIS + " minutes ago";
}
else if(diff < 90 * MINUTE_MILLIS)
{
return "an hour ago";
}
else if(diff < 24 * HOUR_MILLIS)
{
return diff / HOUR_MILLIS + " hours ago";
}
else if(diff < 48 * HOUR_MILLIS)
{
return "yesterday";
}
else
{
return diff / DAY_MILLIS + " days ago";
}
}
使用方法:
只需调用该方法并以milliseconds
传递时间。
例如:
long now = System.currentTimeMillis();
getTimeAgo(now);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.