繁体   English   中英

如何在C#程序中使用互斥代码?

[英]How to use the mutex code in a C# program?

我已经完成了互斥锁的代码,但它给了我错误,如:

public override void dispose(bool disposing); 找不到合适的处理方法

这是在初始化组件上发生的,所以我评论了那个部分,但我面临的主要错误是在设计视图部分:

设计者无法在第26行处理代码:throw new NotImplementedException(); 方法'InitializeComponent'中的代码由设计者生成,不应手动修改。 请删除所有更改,然后再次尝试打开设计器。

我无法查看form.cs [design]。 我怎样才能解决这个问题?

Program.cs中:

using System;
using System.Collections.Generic;
using System.Windows.Forms;
using PU;

namespace WindowsApplication1
{
    static class Program
    {
        [STAThread]
        static void Main()
        {
            // If this program is already running, set focus
            // to that instance and quit.
            if (ProcessUtils.ThisProcessIsAlreadyRunning())
            {
                // "Form1" is the caption (Text property) of the main form.
                ProcessUtils.SetFocusToPreviousInstance("Form1");
            }
            else
            {
                Application.EnableVisualStyles();
                Application.SetCompatibleTextRenderingDefault(false);
                Application.Run(new Form1());
            }
        }
    }
}

ProcessUtils.cs:

using System;
using System.Diagnostics;
using System.Threading;
using System.Windows.Forms;
using System.Runtime.InteropServices;

namespace PU
{
    /// Summary description for ProcessUtils.
    public static class ProcessUtils
    {
        private static Mutex mutex = null;

        /// Determine if the current process is already running
        public static bool ThisProcessIsAlreadyRunning()
        {
            // Only want to call this method once, at startup.
            Debug.Assert(mutex == null);

            // createdNew needs to be false in .Net 2.0, otherwise, if another instance of
            // this program is running, the Mutex constructor will block, and then throw 
            // an exception if the other instance is shut down.
            bool createdNew = false;

            mutex = new Mutex(false, Application.ProductName, out createdNew);

            Debug.Assert(mutex != null);

            return !createdNew;
        }

        [DllImport("user32.dll", SetLastError = true)]
        static extern IntPtr FindWindow(string lpClassName, string lpWindowName);

        [DllImport("user32.dll")]
        [return: MarshalAs(UnmanagedType.Bool)]
        static extern bool SetForegroundWindow(IntPtr hWnd);

        [DllImport("user32.dll")]
        static extern bool IsIconic(IntPtr hWnd);

        [DllImport("user32.dll")]
        static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);

        const int SW_RESTORE = 9;

        [DllImport("user32.dll")]
        static extern IntPtr GetLastActivePopup(IntPtr hWnd);

        [DllImport("user32.dll")]
        static extern bool IsWindowEnabled(IntPtr hWnd);

        /// Set focus to the previous instance of the specified program.
        public static void SetFocusToPreviousInstance(string windowCaption)
        {
            // Look for previous instance of this program.
            IntPtr hWnd = FindWindow(null, windowCaption);

            // If a previous instance of this program was found...
            if (hWnd != null)
            {
                // Is it displaying a popup window?
                IntPtr hPopupWnd = GetLastActivePopup(hWnd);

                // If so, set focus to the popup window. Otherwise set focus
                // to the program's main window.
                if (hPopupWnd != null && IsWindowEnabled(hPopupWnd))
                {
                    hWnd = hPopupWnd;
                }

                SetForegroundWindow(hWnd);

                // If program is minimized, restore it.
                if (IsIconic(hWnd))
                {
                    ShowWindow(hWnd, SW_RESTORE);
                }
            }
        }
    }
}

如果你真的试图覆盖“处置”方法那么它就是套管问题 - 它是Dispose ,而不是dispose C#区分大小写。

至于其他问题,很难说你还没有提供足够的信息来说明你在做什么。 如果你开始告诉我们更多你的情况,这将有所帮助。 你到底做了什么? 互斥体在哪里进入?

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM