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[英]Ruby on Rails: How to get the current week and loop through it to display its days?
[英]How can I loop through each of the days of a given week in Ruby?
我使用以下命令定义星期一和星期五:
@monday = Date.today.at_beginning_of_week
@friday = 5.days.since(@monday)
但是实际上,对于任何一天,我实际上都需要遍历星期一,星期二,星期三,并采用该日期并将输出放入一栏中。
<th>Monday</th>
<th>Tuesday</th>
etcetera
例如,给定的行将是:
<tr><td>method_with_arg(monday)</td><td>method_with_arg(tuesday)</td><td>method_with_arg(wednesday)</td></tr>
这是value是采用args date方法的地方。
什么是最干净的方法?
谢谢。
def dates_week(d)
(d.beginning_of_week...d.beginning_of_week+5).map{|a|
"<td>#{a.strftime('%F')}</td>"
}.join
end
dates_week Date.today
#=> "<td>2010-05-17</td><td>2010-05-18</td><td>2010-05-19</td><td>2010-05-20</td><td>2010-05-21</td>"
代替a.strftime
您可以调用任何其他方法来接收Date并返回字符串,例如mails_sent_on(a)
等。您还可以使用yield a
there通过block传递与日期相关的逻辑:
def dates_week(d)
(d.beginning_of_week...d.beginning_of_week+5).map{|a|
yield a
}.join
end
dates_week(Date.today) { |d|
"<td>#{mails_sent_on(d)}</td>"
}
或者,将字符串保留在dates_week
方法之外:
def dates_week(d)
(d.beginning_of_week...d.beginning_of_week+5).map{|a|
yield a
}
end
dates_week(Date.today) { |d|
mails_sent_on(d)
}.join(', ')
或您需要的任何形式。
我只是使用Plain Old Ruby Objects,但是我想如果您想使事物保持干燥,则希望将工作日的逻辑与工作日的用途分开。
def dates_week(d)
d.beginning_of_week...(d.beginning_of_week+5)
end
dates_week(Date.today).map {|a|
"<td>#{a.strftime('%F')}</td>"
}.join
我会比安德鲁走得更远,并且需要一个步骤:
def dates_week(d, delim)
"<tr>" + (d.beginning_of_week...(d.beginning_of_week+5)).map do |day|
"<#{delim}> #{yield(day)} </#{delim}>"
end.join + "</tr>"
end
dates_week(Date.today, "th") {|d| d.strftime("%A")} # => <tr><th>Monday</th><th>Tuesday</th>...
dates_week(Date.today, "td") {|d| some_function(d)} #first row
我能想到的最简单的解决方案是:
first_day = Date.today.at_beginning_of_week
days = 7.times.map {|x| first_day + x.days }
days.each do |day|
puts "<td>" + func(day) + "</td>"
end
这应该够了吧
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