Django：当父模型有两个外键来自同一模型时，如何定义模型？

Question

我想在父模型中定义两个模型字段：created_by，modified_by，它们将用作子模型的公共字段。

class ExtendedModel(models.Model):
        created_by = models.ForeignKey(User,related_name='r_created_by')
        modified_by = models.ForeignKey(User,related_name='r_modified_by')
        class Meta:
                abstract = True

class ChildModel1(ExtendedModel):
        pass

class ChildModel2(ExtendedModel):
        pass

这会产生错误，因为ChildModel1和ChildModel2在created_by和modified_by字段上具有related_name冲突。

Answer 1

Django文档说明了如何解决此问题： http : //docs.djangoproject.com/en/dev/topics/db/models/#abstract-related-name

class ExtendedModel(models.Model):
        created_by = models.ForeignKey(User,related_name='"%(app_label)s_%(class)s_created_by')
        modified_by = models.ForeignKey(User,related_name='"%(app_label)s_%(class)s_modified_by')
        class Meta:
                abstract = True

class ChildModel1(ExtendedModel):
        pass

class ChildModel2(ExtendedModel):
        pass