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Java服务器处理客户端请求并对其进行响应?

[英]Java server to handle Client requests and respond to it?

我正在寻找创建Java Server来处理客户端请求并对其进行响应的概念,我想使用不允许Socket连接的Google App引擎,那么在这种情况下客户端和服务器是否可以使用Http请求进行通信? 如果有人可以向我阐明逻辑并提供几行代码,我将非常高兴。

谢谢

简单框架可能会提供您想要的东西。 它允许您以相对较少的开销将HTTP服务器嵌入到您的应用程序中:

import org.simpleframework.http.core.Container;
import org.simpleframework.transport.connect.Connection;
import org.simpleframework.transport.connect.SocketConnection;
import org.simpleframework.http.Response;
import org.simpleframework.http.Request;
import java.net.InetSocketAddress;
import java.net.SocketAddress;
import java.io.PrintStream;

public class HelloWorld implements Container {

   public void handle(Request request, Response response) {
      PrintStream body = response.getPrintStream();
      long time = System.currentTimeMillis();

      response.set("Content-Type", "text/plain");
      response.set("Server", "HelloWorld/1.0 (Simple 4.0)");
      response.setDate("Date", time);
      response.setDate("Last-Modified", time);

      body.println("Hello World");
      body.close();
   } 

   public static void main(String[] list) throws Exception {
      Container container = new HelloWorld();
      Connection connection = new SocketConnection(container);
      SocketAddress address = new InetSocketAddress(8080);

      connection.connect(address);
   }
}

为了与其他解决方案进行比较,请注意,Simple不仅是可嵌入的,而且是开源的,完全自包含的并且始终是异步的。 祝好运!

感谢所有答案,但我需要一种简单的方法在Android App中使用它,如以下代码所示:

HTTP GET

`

try {
        HttpClient client = new DefaultHttpClient();  
        String getURL = "http://www.google.com";
        HttpGet get = new HttpGet(getURL);
        HttpResponse responseGet = client.execute(get);  
        HttpEntity resEntityGet = responseGet.getEntity();  
        if (resEntityGet != null) {  
                    //do something with the response
                    Log.i("GET RESPONSE",EntityUtils.toString(resEntityGet));
                }
} catch (Exception e) {
    e.printStackTrace();
}`

HTTP POST

try {
    HttpClient client = new DefaultHttpClient();  
    String postURL = "http://somepostaddress.com";
    HttpPost post = new HttpPost(postURL); 
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        params.add(new BasicNameValuePair("user", "kris"));
        params.add(new BasicNameValuePair("pass", "xyz"));
        UrlEncodedFormEntity ent = new UrlEncodedFormEntity(params,HTTP.UTF_8);
        post.setEntity(ent);
        HttpResponse responsePOST = client.execute(post);  
        HttpEntity resEntity = responsePOST.getEntity();  
        if (resEntity != null) {    
            Log.i("RESPONSE",EntityUtils.toString(resEntity));
        }
} catch (Exception e) {
    e.printStackTrace();
}

该代码来自此站点 ,您不需要任何其他Jar文件即可在Android中使用它,并且我将其与Google App引擎一起使用。

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