[英]Passing blocks into nested method within class_eval in Ruby?
我希望能够定义一个块,然后在动态生成的模块/类中评估该块。 似乎我可以使用eval
和block.binding
来完成此block.binding
,但是我还没有弄清楚。
我以此为基础:
def define_module(name, &block)
name = name.to_s.gsub(/\/(.?)/) { "::#{$1.upcase}" }.gsub(/(?:^|_)(.)/) { $1.upcase }
parts = name.split("::")
parts.each_with_index do |part, index|
sub_name = parts[0..index].join("::")
eval("module #{sub_name}; end")
end
clazz = eval(name)
clazz.class_eval(&block) if block_given?
clazz
end
def add_module(name, &block)
module_block = block
define_module(name).class_eval <<-EOF
def self.included(base)
base.class_eval do
# something like this, I'm stuck
instance_eval(&#{module_block})
end
end
EOF
end
我想这样使用它:
add_module("My::Library") do
def a_method
"added 'a_method'"
end
end
class ::User
include My::Library
end
user = ::User.new
assert_equal "added 'a_method'", user.a_method
有什么办法可以做这样的事情吗?
这有效:
def add_module(name, &block)
define_module(name).class_eval do
class << self; self; end.send(:define_method, :included) { |base|
base.class_eval(&block)
}
end
end
add_module("My::Library") do
def a_method
"added 'a_method'"
end
end
class ::User
include My::Library
end
user = ::User.new
user.a_method #=> "added a_method"
编辑:
您为什么不这样做呢? 简单得多,实际上是模块的工作 :
def add_module(name, &block)
define_module(name).class_eval(&block)
end
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