如何为这个表达式写一个正则表达式？

Question

url1 = http://xyz.com/abc
url2 = http://xyz.com//abc

我想编写一个验证url1和url2的regex

Answer 1

为什么不直接使用urlparse呢？

Answer 2

你可以使用这个正则表达式：

\w{4}\:\/{2}\w+\.\w+\/{1,2}\w+

说明：

\w{4} match any word character [a-zA-Z0-9_]
    Quantifier: Exactly 4 times
\: matches the character : literally
\/{2} matches the character / literally
    Quantifier: Exactly 2 times
\w+ match any word character [a-zA-Z0-9_]
    Quantifier: Between one and unlimited times, as many times as possible, giving back as needed
\. matches the character . literally
\w+ match any word character [a-zA-Z0-9_]
    Quantifier: Between one and unlimited times, as many times as possible, giving back as needed
\/{1,2} matches the character / literally
    Quantifier: Between 1 and 2 times, as many times as possible, giving back as needed 
\w+ match any word character [a-zA-Z0-9_]
    Quantifier: Between one and unlimited times, as many times as possible, giving back as needed

希望这可以帮助。

Answer 3

http://\w+\.\w+//?\w+

Answer 4

答案取决于您是否要解析一般的网址，或者您是否只是想知道如何处理可选的斜杠。

在第一种情况下，我同意Amber你应该使用urlparse。

在第二种情况下，使用? 在表达式中的斜杠之后：

http://xyz.com//?abc

一个? 在正则表达式中表示前一个元素是可选的（即可能出现零次或一次）。