MySQL 按 COUNT DISTINCT 排序

Question

2.8.7
2.8.3
2.8.2
2.8.7
2.8.5
2.8.7
2.8.7
2.8.5
2.6.0
2.8.3
2.6.4
2.6.3
2.8.4
2.8.0
2.6.3
2.8.5
2.8.5
2.8.5
2.6.0
2.8.2

我如何带来按这些版本的数量排序的唯一值版本？

在出口处，我想获得以下信息：

2.8.5 5

2.8.7 4

2.6.0 2

2.6.3 2

2.8.2 2

2.8.3 2

2.8.4 2

2.6.4 1

2.8.0 1

ORDER BY 计数唯一版本))

抱歉我的英语不好

Answer 1

SELECT
  version,
  COUNT(*) AS num
FROM
  my_table
GROUP BY
  version
ORDER BY
  COUNT(*) DESC

Answer 2

SELECT version, COUNT(*) FROM tablename
GROUP BY version
ORDER BY COUNT(*) DESC;

或者，替代语法

SELECT version, COUNT(*) FROM tablename
GROUP BY 1
ORDER BY 2 DESC;

Answer 3

select version, count(*) from sometable group by version order by count(*) desc;

Answer 4

不用担心，你的英语是可以理解的。 请找到以下答案：

> SELECT version, COUNT(version) AS quantity
FROM tablename
GROUP BY version

有关详细信息，请参阅http://www.kelvinese.com上的答案