MySQL 按 COUNT DISTINCT 排序

Question

2.8.7
2.8.3
2.8.2
2.8.7
2.8.5
2.8.7
2.8.7
2.8.5
2.6.0
2.8.3
2.6.4
2.6.3
2.8.4
2.8.0
2.6.3
2.8.5
2.8.5
2.8.5
2.6.0
2.8.2

我如何帶來按這些版本的數量排序的唯一值版本？

在出口處，我想獲得以下信息：

2.8.5 5

2.8.7 4

2.6.0 2

2.6.3 2

2.8.2 2

2.8.3 2

2.8.4 2

2.6.4 1

2.8.0 1

ORDER BY 計數唯一版本))

抱歉我的英語不好

Answer 1

SELECT
  version,
  COUNT(*) AS num
FROM
  my_table
GROUP BY
  version
ORDER BY
  COUNT(*) DESC

Answer 2

SELECT version, COUNT(*) FROM tablename
GROUP BY version
ORDER BY COUNT(*) DESC;

或者，替代語法

SELECT version, COUNT(*) FROM tablename
GROUP BY 1
ORDER BY 2 DESC;

Answer 3

select version, count(*) from sometable group by version order by count(*) desc;

Answer 4

不用擔心，你的英語是可以理解的。 請找到以下答案：

> SELECT version, COUNT(version) AS quantity
FROM tablename
GROUP BY version

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