如何从 mysql 日期中提取年、月、日、小时、分钟、秒？

Question

在我的 mysql 数据库中，我有这样的日期：2011-01-06 09:39:114525

我需要从中分别提取年、月、日、小时、分钟、秒。

所以我需要从上面的例子中提取：

2011
01
06
09
39
11

我该怎么做？

Answer 1

在 MySQL 中，只需执行MONTH(date) 、 YEAR(date)等。在 PHP 中，您可以执行date('g', strtotime($datefromsql))来获取，例如，从日期开始的 12 小时格式小时.

所以在你上面的例子中，你可以做

SELECT YEAR(date), 
       MONTH(date), 
       DAYOFMONTH(date), 
       HOUR(date), 
       MINUTE(date), 
       SECOND(date)

或在 PHP 中，

$time = strtotime($datefromsql);
echo date('Y', $time);
echo date('m', $time);
echo date('d', $time);
echo date('h', $time);
echo date('i', $time);
echo date('s', $time);

Answer 2

检查此链接http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html

ADDDATE()   Add time values (intervals) to a date value

ADDTIME()   Add time

CONVERT_TZ()    Convert from one timezone to another

CURDATE()   Return the current date

CURRENT_DATE(), CURRENT_DATE    Synonyms for CURDATE()

CURRENT_TIME(), CURRENT_TIME    Synonyms for CURTIME()

CURRENT_TIMESTAMP(), CURRENT_TIMESTAMP  Synonyms for NOW()

CURTIME()   Return the current time

DATE_ADD()  Add time values (intervals) to a date value

DATE_FORMAT()   Format date as specified

DATE_SUB()  Subtract a time value (interval) from a date

DATE()  Extract the date part of a date or datetime expression

DATEDIFF()  Subtract two dates

DAY()   Synonym for DAYOFMONTH()

DAYNAME()   Return the name of the weekday

DAYOFMONTH()    Return the day of the month (0-31)

DAYOFWEEK()     Return the weekday index of the argument

DAYOFYEAR()     Return the day of the year (1-366)

EXTRACT()   Extract part of a date

FROM_DAYS()     Convert a day number to a date

FROM_UNIXTIME()     Format UNIX timestamp as a date

GET_FORMAT()    Return a date format string

HOUR()  Extract the hour

LAST_DAY    Return the last day of the month for the argument

LOCALTIME(), LOCALTIME  Synonym for NOW()

LOCALTIMESTAMP, LOCALTIMESTAMP()    Synonym for NOW()

MAKEDATE()  Create a date from the year and day of year

MAKETIME    MAKETIME()

MICROSECOND()   Return the microseconds from argument

MINUTE()    Return the minute from the argument

MONTH()     Return the month from the date passed

MONTHNAME()     Return the name of the month

NOW()   Return the current date and time

PERIOD_ADD()    Add a period to a year-month

PERIOD_DIFF()   Return the number of months between periods

QUARTER()   Return the quarter from a date argument

SEC_TO_TIME()   Converts seconds to 'HH:MM:SS' format

SECOND()    Return the second (0-59)

STR_TO_DATE()   Convert a string to a date

SUBDATE()   A synonym for DATE_SUB() when invoked with three arguments

SUBTIME()   Subtract times

SYSDATE()   Return the time at which the function executes

TIME_FORMAT()   Format as time

TIME_TO_SEC()   Return the argument converted to seconds

TIME()  Extract the time portion of the expression passed

TIMEDIFF()  Subtract time

TIMESTAMP()     With a single argument, this function returns the date or datetime expression; with two arguments, the sum of the arguments

TIMESTAMPADD()  Add an interval to a datetime expression

TIMESTAMPDIFF()     Subtract an interval from a datetime expression

TO_DAYS()   Return the date argument converted to days

TO_SECONDS()    Return the date or datetime argument converted to seconds since Year 0

UNIX_TIMESTAMP()    Return a UNIX timestamp

UTC_DATE()  Return the current UTC date

UTC_TIME()  Return the current UTC time

UTC_TIMESTAMP()     Return the current UTC date and time

WEEK()  Return the week number

WEEKDAY()   Return the weekday index

WEEKOFYEAR()    Return the calendar week of the date (0-53)

YEAR()  Return the year

YEARWEEK()  Return the year and week

Answer 3

使用 DateTime 类的最佳方法

$my_sql_date = '2011-01-06 09:39:11';
$date_time = new DateTime($my_sql_date);
echo $date_time->format('Y').PHP_EOL;
echo $date_time->format('m').PHP_EOL;
echo $date_time->format('d').PHP_EOL;
echo $date_time->format('h').PHP_EOL;
echo $date_time->format('i').PHP_EOL;
echo $date_time->format('s');

Answer 4

$dt = Carbon::now();
$dt->timestamp = strtotime($mysqlVarDatetime); //like '2017-01-31 07:19:11' string cad

它可能导致：

var_dump($dt->year);                                         // int(2017)
var_dump($dt->month);                                        // int(1)
var_dump($dt->day);                                          // int(31)
var_dump($dt->hour);                                         // int(7)
var_dump($dt->minute);                                       // int(19)
var_dump($dt->second);                                       // int(11)

碳库更多信息资源： http : //carbon.nesbot.com/docs/#api-getters

Answer 5

旧线程，但我忍不住发布了明显的“蛮力”解决方案：

如果您的 SQL 日期时间字符串格式始终如您的示例所示，并且您不想使用日期时间函数/类，则可以执行以下操作：

$mysql_datetime = "2011-01-06 09:39:114525";
list($date, $time) = explode(' ', $mysql_datetime);
list($year, $month, $day) = explode('-', $date);
list($hr, $min, $sec) = explode(':', $time);
$sec = (int)substr($sec, 0, 2);

您想要的值现在在以下变量中可用： $year, $month, $day, $hr, $min, $sec 。

Answer 6

我想建议一种更清洁的方法。 这可以在没有任何库或框架的情况下实现。

首先，您应该将日期时间字符串转换为时间戳（ strtotime几乎适用于所有格式）。 然后使用getdate如下：

$dateAsTimestamp = strtotime("2011-01-06 09:39:11.45");
$dateTime = getdate($dateAsTimestamp);

该函数将日期和时间的所有组件作为关联数组返回。

Array
(
    [seconds] => 11
    [minutes] => 39
    [hours] => 9
    [mday] => 6
    [wday] => 4
    [mon] => 1
    [year] => 2011
    [yday] => 5
    [weekday] => Thursday
    [month] => January
    [0] => 1294306751
)

现在可以根据您的要求访问

echo($dateTime['hours']);
echo($dateTime['minutes']);
echo($dateTime['seconds']);

$MONTH = $dateTime['month'];

更多关于日期/时间函数 - getdate和strtotime