[英]How to use the equivalent of indexof() with biginteger in VB.Net?
我试图将大量数字相加。 我已经知道了数字的长度
l = answer.bitLength()
但我无法弄清楚如何使用For循环遍历每个数字。 有任何想法吗?
我正在使用java.math.biginteger
。
Visual Studio 2005版本2.0
我还应该补充一点,我似乎无法在正在使用的biginteger中使用<>或任何简单的数学选项。 如果有人可以告诉我如何使用其他biginteger,我将更愿意交换。
Dim answer As java.math.BigInteger
Dim sum As Integer = 0
Dim x As Integer
Dim i As Integer
'Sets value of answer equal to 1
answer = java.math.BigInteger.valueOf(1)
'gets 100!
For i = 1 To 100
answer = answer.multiply(java.math.BigInteger.valueOf(i))
Next
'gets length of answer
Dim l As Integer
l = answer.bitLength()
'Sums up digits in 100!
For x = 0 To l - 1
'Need to pull each character here to add them all up
Next
汇总数字的最终解决方案。 多亏了efoghe。
Dim r As Integer
Dim s As Integer
s = 0
While (answer.compareTo(java.math.BigInteger.valueOf(0)) > 0)
r = answer.mod(java.math.BigInteger.valueOf(10)).ToString()
s = s + r
answer = answer.divide(java.math.BigInteger.valueOf(10))
End While
这样的事情应该起作用:
Dim bi As New System.Numerics.BigInteger(12345)
Dim c As Char
Dim s As Long
s = 0
For Each c In bi.ToString()
s = s + Integer.Parse(c.ToString())
Next
或者使用Mod和/(整数除法)的这种更常规的方式
Dim bi As New System.Numerics.BigInteger(12345)
Dim s As Long
Dim r As Integer
s = 0
While bi <> 0
r = bi Mod 10
s = s + r
bi = bi / 10
End While
另一种方法是执行以下操作(假定answer
是肯定的):
int sum = 0;
while(answer > 0){
sum += answer % 10;
answer /= 10;
}
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