Haskell函数返回空列表

Question

我真的是Haskell的绝对新手，所以我完全不知道如何调试我写的一些函数。 当我打电话给shuntingYard ["3+4"]我回来[] ，而我想回来[34+] 。 任何和所有的帮助将非常非常感谢。

import Char

isOperator :: Char -> Bool
isOperator x = elem x ['+','-','*','/','%','^','!','=','<','>']

associativityOf :: Char -> String
associativityOf x = if elem x ['+','-','*','/','%']
                    then "Left"
                    else "Right"

precedenceOf :: Char -> Int
precedenceOf x
    | elem x "=<>"   = 1 
    | elem x "+-"    = 2
    | elem x "*/%"   = 3
    | elem x "^!"    = 4
    | otherwise      = 0

operatorActions :: [[Char]] -> [[Char]] -> [[Char]]
operatorActions stmt stack
    | ( tokenAssoc == "Left"  && tokenPrecedence <= stackPrecedence ) ||        
      ( tokenAssoc == "Right" && tokenPrecedence <  stackPrecedence ) =
        [stackOper] : _shuntingYard stmt (tail stack)
    | otherwise   = _shuntingYard (tail stmt) ((head stmt) : stack)
    where tokenAssoc       = associativityOf (head (head stmt))
          tokenPrecedence  = precedenceOf    (head (head stmt))
          stackOper        = if (not (null stack))
                           then (head (head stack))
                           else '='
          stackPrecedence  = precedenceOf stackOper

stackOperations :: [[Char]] -> [[Char]]                                
stackOperations stack
    | ((not (null stack)) && (head (head stack)) == '(') = 
      error "Unbalanced parens."
    | null stack = []
    | otherwise  = (head stack) : _shuntingYard [] (tail stack)

_shuntingYard :: [[Char]] -> [[Char]] -> [[Char]]
_shuntingYard stmt stack
    | null stmt          = stackOperations stack
    | all isDigit (head stmt) = (head stmt) : _shuntingYard (tail stmt) stack
    | isOperator  (head (head stmt)) = operatorActions stmt stack
    | (head (head stmt)) == '('=
      _shuntingYard (tail stmt) ((head stmt) : stack)
    | (head (head stmt)) == ')' = if (head (head stack)) == '('
                            then _shuntingYard (tail stmt) (tail stack)
                            else (head stack) : _shuntingYard stmt (tail stack)
    | otherwise = _shuntingYard (tail stmt) stack

shuntingYard :: [[Char]] -> [[Char]]
shuntingYard stmt = _shuntingYard stmt []

Answer 1

作为一般调试技术，您可以使用Debug.Trace模块找出正在调用的函数以及它们的输入内容。 使用每个步骤后查看算法的状态。

import Debug.Trace

-- Show arguments each time _shuntingYard is called
_shuntingYard :: [[Char]] -> [[Char]] -> [[Char]]
_shuntingYard stmt stack = traceShow (stmt, stack) $ __shuntingYard stmt stack

__shuntingYard stmt stack
  | null stmt = stackOperations stack
  {- etcetera -}

这打印：

(["3+4"],[])
([],[])

嗯，你在第一次通话后失去了一切。 看着__shuntingYard中的警卫，看来“其他”案件被调用了。

也许你想打电话给shuntingYard ["3", "+", "4"] ？

Answer 2

好的，让我们来看看当你打电话给shuntingYard ["3+4"]时会发生什么：

1. 它叫_shuntingYard ["3+4"] []
2. 它通过_shuntingYard的守卫：
   1. null stmt = null ["3+4"] = false
   2. all isDigit (head stmt) = all isDigit "3+4" = false因为+不是数字
   3. isOperator (head (head stmt)) = isOperator '3' = false
   4. 也错误为'3' /= '('
   5. 也错误为'3' /= ')'
3. 由于没有一个守卫匹配，所以我们进入默认情况并调用_shuntingYard (tail stmt) stack = _shuntingYard [] []
4. 这次第一个保护（ null stmt = null [] ）匹配，所以我们调用stackOperations []并获取[] 。