SQL select from table where key in array group by column

Question

给定一张表账单

# bills
id  | name    | amount  | user_id
1   | jumper  | 100     | 1
2   | gopper  | 200     | 1
3   | jumper  | 150     | 2
4   | blobber | 300     | 3

和一个表用户

# users
id  | name
1   | John Doe
2   | Mike Marley
3   | Bill Mickane

当我执行查询时

select * from bills where user_id in (1,2) order by name, amount desc

我明白了

# bills
id  | name    | amount  | user_id
2   | gopper  | 200     | 1
3   | jumper  | 150     | 2
1   | jumper  | 100     | 1

但我想要的是（和所有其他专栏）

# bills
name    | amount
gopper  | 200   
jumper  | 250   

这将如何实现？

我很想用

select * from bills where user_id in (1,2) group by name order by name, amount desc

但不能作为group by还需要列出其他列名，最终不会根据需要合并两行。

ps 我正在使用 postgresql

Answer 1

如果您只想要这两个字段，您可以使用 Aggregate SUM()：

 SELECT 
          name, 
          SUM(amount) 
     FROM 
          bills 
     WHERE 
          user_id IN (1,2) 
     GROUP BY 
          name 
     ORDER BY 
          name, 
          amount

但是，假设您想要的不仅仅是这两个字段......嵌套查询应该可以帮助您。

SELECT
 m.id, m.name, t.userId, t.amount 
FROM Bills m
 INNER JOIN
 (
   SELECT
          user_id as userID,
          SUM(amount) as amount
   FROM
          bills
   GROUP BY user_id
 ) t
ON t.UserID = m.UserID

Answer 2

SELECT 
    name, SUM(amount) 
FROM 
    bills 
WHERE 
    user_id IN (1,2) 
GROUP BY 
    name 
ORDER BY 
    name, amount DESC

Answer 3

SELECT name, SUM(amount) as amount
FROM bills where user_id IN (1,2) 
GROUP BY name
ORDER BY name, amount DESC

Answer 4

select name, sum(amount) as amount
from bills where user_id in (1,2) 
group by name 
order by name, amount desc