[英]Row_Number simulation in Sql server 2000
我有一个示例输入表
Declare @input TABLE(Name VARCHAR(8))
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Joseph')
INSERT INTO @input(Name) values('Vicky')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Vicky')
INSERT INTO @input(Name) values('Padukon')
INSERT INTO @input(Name) values('Aryan')
INSERT INTO @input(Name) values('Jaesmin')
INSERT INTO @input(Name) values('Vick')
INSERT INTO @input(Name) values('Padukon')
INSERT INTO @input(Name) values('Joseph')
INSERT INTO @input(Name) values('Marya')
INSERT INTO @input(Name) values('Vicky')
我也有一个理货桌子如下
declare @t table(n int)
insert into @t select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9 union all select 10 union all select 11 union all
select 12 union all select 13 union all select 14 union all
select 15 union all select 16 union all select 17 union all
select 18 union all select 19 union all select 20
在Sql Server 2005中,如果我这样做
Select rn, name from (
select ROW_NUMBER()over (order by Name) as rn , * from @input) x
where rn % 2 <> 0
我得到的输出为
rn name
1 Aryan
3 Aryan
5 Jaesmin
7 Jaesmin
9 Joseph
11 Padukon
13 Vick
15 Vicky
我只能使用Sql Server2000。如何获得相同的输出?
我尝试过
SELECT name, (SELECT COUNT(*) FROM @input AS i2 WHERE i2.Name <= i1.Name) As rn
FROM @input AS i1
但是输出错误
name rn
Aryan 4
Aryan 4
Joseph 9
Vicky 16
Jaesmin 7
Aryan 4
Jaesmin 7
Vicky 16
Padukon 12
Aryan 4
Jaesmin 7
Vick 13
Padukon 12
Joseph 9
Marya 10
Vicky 16
将您的表变量声明为
Declare @input TABLE(_id int identity(1, 1), Name VARCHAR(8))
然后重新查询为
Select _id, name
from @input
where _id % 2 <> 0
使用此查询:
SELECT t1.name, t.n
FROM
(
SELECT a.name, a.c, (SELECT COUNT(*) FROM @input AS i2 WHERE i2.Name <= a.Name) [rn]
FROM
(
SELECT i.name, count(*) c
FROM @input i
GROUP BY i.name
)a
)t1
JOIN @t t ON t.n <= t1.rn
WHERE t.n > t1.rn - t1.c
它产生所需的输出:
name n
-------- -----------
Aryan 1
Aryan 2
Aryan 3
Aryan 4
Jaesmin 5
Jaesmin 6
Jaesmin 7
Joseph 8
Joseph 9
Marya 10
Padukon 11
Padukon 12
Vick 13
Vicky 14
Vicky 15
Vicky 16
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