[英]Symfony Insert SQL Error - a foreign key constraint fails
我正在使用夹具为我的 symfony 项目生成数据,但由于某种原因,不断抛出以下错误:
无法执行 INSERT 语句。 [包装:SQLSTATE [23000]:完整性约束违规:1452无法添加或更新子行:外键约束失败(
meeting
。会议参加,约束会议meeting_id
meeting_attendance_FK_1
meeting_attendance
外meeting_meetings
(会议ID)参考会议会议(id
))]
我正在寻找发生错误的原因,我正在使用 Symfony 1.4,带有推进力和 MySQL 数据库。
会议方案和出席方案如下,完整副本在http://pastebin.com/HZhaqWSN
meeting_meetings:
id: ~
owner_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
group_id: { type: integer, foreignTable: meeting_groups, foreignReference: id }
name: { type: varchar, required: true, default: Meeting }
completed: { type: boolean, required: true, default: 0 }
location: { type: varchar, required: true, default: Unknown }
start: { type: integer, required: true }
length: { type: integer, required: true, default: 60 }
created_at: ~
updated_at: ~
meeting_attendance:
id: ~
meeting_id: { type: integer, foreignTable: meeting_meetings, foreignReference: id, required: true }
user_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
invited: { type: boolean, required: true, default: 0 }
attending: { type: boolean, required: true, default: 0 }
apolgies: { type: boolean, required: true, default: 0 }
attended: { type: boolean, required: true, default: 0 }
apolgies_comment: { type: varchar(255) }
03_meetings.yml如下
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
和 09_attendance.yml 如下:
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
apolgies_comment: None
我的两个灯具都使用 PHP 随机生成,但我已将它们更改为上述以尝试定位此错误!
我想我一定忽略了一些简单的事情,但是我已经尝试调试了一个多小时,而且我束手无策!
有谁知道是什么导致了这个错误或如何解决它?
非常感谢您的时间,
编辑:有人建议将所有内容放在一个文件中,我已经这样做了,并使用 php 运行该文件(以确切了解正在读取的内容)。 它仍然得到同样的错误:
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
MeetingItems:
Item1:
Value: VfH0qXxGV4Ylb ZtRm DKkDE9dTzlWR z Nm TnNhxVPvZO eOn IM5 v ETOl v 4 xsA7HexNwzB YDvz I uay Sjm3rbAu iaiZIPGv l0oNSFCG To
MeetingAgendas:
Agenda1:
MeetingId: PezMeeting
ItemId: Item1
MeetingActions:
Action1:
ItemId: Item1
MeetingId: PezMeeting
Due: 1310705295
Start: 1310358321
Completed: 1
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
仍然得到:
Unable to execute INSERT statement. [wrapped: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`meeting`.`meeting_agendas`, CONSTRAINT `meeting_agendas_FK_1` FOREIGN KEY (`meeting_id`) REFERENCES `meeting_meetings` (`id`))]
编辑 2:为表格生成的 SQL 在这里: http://pastebin.com/XQmM3k7S (下面的一些表格)DROP TABLE IF EXISTS meeting_meetings
;
CREATE TABLE `meeting_meetings`
(
`id` INTEGER NOT NULL AUTO_INCREMENT,
`owner_id` INTEGER NOT NULL,
`group_id` INTEGER,
`name` VARCHAR(255) default 'Meeting' NOT NULL,
`completed` TINYINT default 0 NOT NULL,
`location` VARCHAR(255) default 'Unknown' NOT NULL,
`start` INTEGER NOT NULL,
`length` INTEGER default 60 NOT NULL,
`created_at` DATETIME,
`updated_at` DATETIME,
PRIMARY KEY (`id`),
INDEX `meeting_meetings_FI_1` (`owner_id`),
CONSTRAINT `meeting_meetings_FK_1`
FOREIGN KEY (`owner_id`)
REFERENCES `sf_guard_user_profile` (`user_id`),
INDEX `meeting_meetings_FI_2` (`group_id`),
CONSTRAINT `meeting_meetings_FK_2`
FOREIGN KEY (`group_id`)
REFERENCES `meeting_groups` (`id`)
)Type=InnoDB;
此固定装置必须在同一个文本文档中以帮助保存!
这个夹具必须在同一个文件中。 我的意思是来自 03_meetings.yml 和 09_attendance.yml 的固定装置
我希望这会有用。
在 config/ProjectConfiguration.class.php 中试试这个。 然后在数据加载后将其注释掉。
class ProjectConfiguration extends sfProjectConfiguration
{
public function setup()
{
// ...
}
public function configureDoctrine(Doctrine_Manager $manager)
{
$manager->setAttribute(Doctrine_Core::ATTR_QUOTE_IDENTIFIER, true);
}
}
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