[英]Symfony Insert SQL Error - a foreign key constraint fails
我正在使用夾具為我的 symfony 項目生成數據,但由於某種原因,不斷拋出以下錯誤:
無法執行 INSERT 語句。 [包裝:SQLSTATE [23000]:完整性約束違規:1452無法添加或更新子行:外鍵約束失敗(
meeting
。會議參加,約束會議meeting_id
meeting_attendance_FK_1
meeting_attendance
外meeting_meetings
(會議ID)參考會議會議(id
))]
我正在尋找發生錯誤的原因,我正在使用 Symfony 1.4,帶有推進力和 MySQL 數據庫。
會議方案和出席方案如下,完整副本在http://pastebin.com/HZhaqWSN
meeting_meetings:
id: ~
owner_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
group_id: { type: integer, foreignTable: meeting_groups, foreignReference: id }
name: { type: varchar, required: true, default: Meeting }
completed: { type: boolean, required: true, default: 0 }
location: { type: varchar, required: true, default: Unknown }
start: { type: integer, required: true }
length: { type: integer, required: true, default: 60 }
created_at: ~
updated_at: ~
meeting_attendance:
id: ~
meeting_id: { type: integer, foreignTable: meeting_meetings, foreignReference: id, required: true }
user_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
invited: { type: boolean, required: true, default: 0 }
attending: { type: boolean, required: true, default: 0 }
apolgies: { type: boolean, required: true, default: 0 }
attended: { type: boolean, required: true, default: 0 }
apolgies_comment: { type: varchar(255) }
03_meetings.yml如下
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
和 09_attendance.yml 如下:
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
apolgies_comment: None
我的兩個燈具都使用 PHP 隨機生成,但我已將它們更改為上述以嘗試定位此錯誤!
我想我一定忽略了一些簡單的事情,但是我已經嘗試調試了一個多小時,而且我束手無策!
有誰知道是什么導致了這個錯誤或如何解決它?
非常感謝您的時間,
編輯:有人建議將所有內容放在一個文件中,我已經這樣做了,並使用 php 運行該文件(以確切了解正在讀取的內容)。 它仍然得到同樣的錯誤:
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
MeetingItems:
Item1:
Value: VfH0qXxGV4Ylb ZtRm DKkDE9dTzlWR z Nm TnNhxVPvZO eOn IM5 v ETOl v 4 xsA7HexNwzB YDvz I uay Sjm3rbAu iaiZIPGv l0oNSFCG To
MeetingAgendas:
Agenda1:
MeetingId: PezMeeting
ItemId: Item1
MeetingActions:
Action1:
ItemId: Item1
MeetingId: PezMeeting
Due: 1310705295
Start: 1310358321
Completed: 1
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
仍然得到:
Unable to execute INSERT statement. [wrapped: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`meeting`.`meeting_agendas`, CONSTRAINT `meeting_agendas_FK_1` FOREIGN KEY (`meeting_id`) REFERENCES `meeting_meetings` (`id`))]
編輯 2:為表格生成的 SQL 在這里: http://pastebin.com/XQmM3k7S (下面的一些表格)DROP TABLE IF EXISTS meeting_meetings
;
CREATE TABLE `meeting_meetings`
(
`id` INTEGER NOT NULL AUTO_INCREMENT,
`owner_id` INTEGER NOT NULL,
`group_id` INTEGER,
`name` VARCHAR(255) default 'Meeting' NOT NULL,
`completed` TINYINT default 0 NOT NULL,
`location` VARCHAR(255) default 'Unknown' NOT NULL,
`start` INTEGER NOT NULL,
`length` INTEGER default 60 NOT NULL,
`created_at` DATETIME,
`updated_at` DATETIME,
PRIMARY KEY (`id`),
INDEX `meeting_meetings_FI_1` (`owner_id`),
CONSTRAINT `meeting_meetings_FK_1`
FOREIGN KEY (`owner_id`)
REFERENCES `sf_guard_user_profile` (`user_id`),
INDEX `meeting_meetings_FI_2` (`group_id`),
CONSTRAINT `meeting_meetings_FK_2`
FOREIGN KEY (`group_id`)
REFERENCES `meeting_groups` (`id`)
)Type=InnoDB;
此固定裝置必須在同一個文本文檔中以幫助保存!
這個夾具必須在同一個文件中。 我的意思是來自 03_meetings.yml 和 09_attendance.yml 的固定裝置
我希望這會有用。
在 config/ProjectConfiguration.class.php 中試試這個。 然后在數據加載后將其注釋掉。
class ProjectConfiguration extends sfProjectConfiguration
{
public function setup()
{
// ...
}
public function configureDoctrine(Doctrine_Manager $manager)
{
$manager->setAttribute(Doctrine_Core::ATTR_QUOTE_IDENTIFIER, true);
}
}
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