繁体   English   中英

需要帮助“关键字GROUP附近的语法不正确”

[英]Need help with “Incorrect syntax near keyword GROUP”

我不知道我在做什么错。 我不断收到不正确的语法错误,好像我纠正了一个,然后弹出了下一行。 现在,我在关键字GROUP上收到“语法不正确。在此网站上,我有几个版本的问题。到目前为止,我非常感谢您的帮助。我只需要进行一些改进即可使此报告生效。任何人都知道明尼苏达州sql的良好类。这些书涵盖了基础知识,我需要复杂的sql类。

SELECT fgc, sum(Totpay) as Totpay, Sum(TotChg) as TotChg
from
(                     
    SELECT fgc, sum(pay) as TotPay, 0 as TotChg
    from 
    (
        SELECT fgc, pay,
               CASE 
                   WHEN  [date]<= 30 THEN 'pmt 0-30'      
                   WHEN [date]> 30 AND [date] <= 60 THEN 'pmt 30-60'
                   WHEN [date]> 61 AND [date] <= 90 THEN 'pmt 61-90'
                   WHEN [date]> 91 AND [date] <= 120 THEN 'pmt 91-120'
                   WHEN [date]> 121 AND [date] <= 150 THEN 'pmt 121-150'
                   WHEN [date]> 151 AND [date] <= 180 THEN 'pmt 151-180'
                   ELSE 'pmt 181+' 
               END
        FROM @Pay 
        GROUP BY fgc

        UNION

        SELECT fgc, 0 as TotPay, sum(chg) as TotChg
        from
        (
            SELECT fgc, chg,
                   CASE 
                       WHEN [date]<= 30 THEN 'charge 0-30'      
                       WHEN [date]> 30 AND [date] <= 60 THEN 'charge 30-60' 
                       WHEN [date]> 61 AND [date] <= 90 THEN 'charge 61-90'
                       WHEN [date]> 91 AND [date] <= 120 THEN 'charge 91-120'
                       WHEN [date]> 121 AND [date] <= 150 THEN 'charge 121-150'
                       WHEN [date]> 151 AND [date] <= 180 THEN 'charge 151-180'
                       ELSE 'charge 181+' 
                   END
            FROM @Chg
        )
        GROUP BY fgc 
    )
    GROUP BY fgc

您没有将别名用于内联查询。 以下没有给我任何语法错误。

        SELECT fgc, sum(Totpay) as Totpay, Sum(TotChg) as TotChg
        from
        (                     
        SELECT fgc, sum(pay) as TotPay, 0 as TotChg
        from 
            (SELECT fgc, pay,
                CASE 
                WHEN  [date]<= 30 THEN 'pmt 0-30'      
                WHEN [date]> 30 AND [date] <= 60 THEN 'pmt 30-60'
                WHEN [date]> 61 AND [date] <= 90 THEN 'pmt 61-90'
                WHEN [date]> 91 AND [date] <= 120 THEN 'pmt 91-120'
                WHEN [date]> 121 AND [date] <= 150 THEN 'pmt 121-150'
                WHEN [date]> 151 AND [date] <= 180 THEN 'pmt 151-180'
                ELSE 'pmt 181+' 
                END
            FROM @Pay 
            GROUP BY fgc 

            UNION

            SELECT fgc, 0 as TotPay, sum(chg) as TotChg
            from
                (SELECT fgc, chg,
                    CASE 
                    WHEN [date]<= 30 THEN 'charge 0-30'      
                    WHEN [date]> 30 AND [date] <= 60 THEN 'charge 30-60' 
                    WHEN [date]> 61 AND [date] <= 90 THEN 'charge 61-90'
                    WHEN [date]> 91 AND [date] <= 120 THEN 'charge 91-120'
                    WHEN [date]> 121 AND [date] <= 150 THEN 'charge 121-150'
                    WHEN [date]> 151 AND [date] <= 180 THEN 'charge 151-180'
                    ELSE 'charge 181+' 
                    END
                 FROM @Chg) as innerTable2
             GROUP BY fgc 
            ) As innertable1
        GROUP BY fgc
    )  as outerTable

基本上,在使用聚合函数的情况下使用GROUP BY关键字,并且要使用它,必须在不使用聚合函数的情况下对所有列进行分组。

例如:代替GROUP BY fgc,应使用GROUP BY(fgc,pay,aliasName)。

更改:

SELECT fgc,付款,当[date] <= 30 THEN'pmt 0-30'时
当[日期]> 30 AND [日期] <= 60则'pmt 30-60'当[日期]> 61 AND [日期] <= 90则[日期]> 91 AND [日期] <= 120 THEN'pmt 91-120'when [date]> 121 and [date] <= 150 THEN'pmt 121-150'when [date]> 151 AND [date] <= 180 THEN'pmt 151-180' ELSE'pmt 181+'结束于@Pay GROUP BY fgc

进入

SELECT fgc,付款,当[date] <= 30 THEN'pmt 0-30'时
当[日期]> 30 AND [日期] <= 60则'pmt 30-60'当[日期]> 61 AND [日期] <= 90则[日期]> 91 AND [日期] <= 120 THEN'pmt 91-120'when [date]> 121 and [date] <= 150 THEN'pmt 121-150'when [date]> 151 AND [date] <= 180 THEN'pmt 151-180' ELSE'pmt 181+'END作为别名,来自@Pay GROUP BY(fgc,pay,别名)

希望能有所帮助。

P / S:tks Gabe纠正了我。

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM