繁体   English   中英

使用通用隐式运算符有什么问题?

[英]what is wrong with this using generic implicit operator?

如果我在非通用生成器类中使用隐式运算符,则一切正常:

 public class ReligionBuilder
{
    private Religion _religion;

    public ReligionBuilder()
    {
        _religion = new Religion(){//some codes}

    }

    public ReligionBuilder AddToRepository()
    {
        Repository<Religion>.Add(_religion);
        return this;
    }
    public Religion Build()
    {
        return _religion;
    }

    public static implicit operator Religion(ReligionBuilder _builder)
    {
        return _builder.Build();

    }
}

我可以使用它:

 Religion religion=new ReligionBuilder().AddToRepository();

但是如果此运算符在通用类中,那是错误的:

 public abstract class DataTestBuilderBase<T> : IDataTestBuilder<T>
{
    protected T TestData { get; set; }

    public virtual T Build()
    {
        return TestData;
    }

    public abstract IDataTestBuilder<T> AddToRepository();
    public abstract IDataTestBuilder<T> WithDefault();

    public static implicit operator T(DataTestBuilderBase<T> builder)
    {
        return builder.Build();
    }
}


 public class PersonDataTestBuilder : DataTestBuilderBase<Person>
{
    private Person _person;

    public PersonDataTestBuilder()
    {
        //some codes
    }
    public override IDataTestBuilder<Person> AddToRepository()
    {
       //some codes
        return this;
    }
}

用法:

 PersonDataTestBuilder _testBuilder = new PersonDataTestBuilder();
        Person person = _testBuilder.AddToRepository();

错误是:无法将IDataTestBuilder转换为Person

问题是什么?

AddToRepository只返回IDataTestBuilder<Person> (在编译时返回类型而言) -而且也没有隐式转换Person 如果将抽象方法的返回类型更改为DataTestBuilderBase<T>则它应该可以工作-尽管坦率地说,我还是不想使用DataTestBuilderBase<T>式转换。 我通常对提供隐式转换非常谨慎-就像我相信的那样,它们通常会使代码不清楚。

无论如何,您是否真的应该在构建器上提供AddToRepository 对于构建者来说,这感觉像是不适当的操作-我期望:

Person person = new PersonBuilder { /* properties */ }
                     .Build()
                     .AddToRepository();

编辑:只是为了显示我的意思,关于更改AddToRepository的返回类型,这是一个简短而完整的程序来演示。 工作正常。

using System;

public abstract class BuilderBase<T>
{
    public abstract T Build();
    public abstract BuilderBase<T> AddToRepository();

    public static implicit operator T(BuilderBase<T> builder)
    {
        return builder.Build();
    }
}

public class TestBuilder : BuilderBase<string>
{
    public override string Build()
    {
        return "Built by Build()";
    }

    public override BuilderBase<string> AddToRepository()
    {
        return this;
    }
}

class Program
{
    static void Main(string[] args)
    {
        string x = new TestBuilder().AddToRepository();
        Console.WriteLine(x);
    }
}

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM