[英]Applet and Servlet communication
我有一个applet,需要将分数提交到servlet,并且它无法正常工作。
这是小程序的代码
private URLConnection getConnection() throws MalformedURLException, IOException {
URL serverAddress = null;
URLConnection conn = null;
serverAddress = new URL("http://localhost/GamesPortal/submitScore");
conn = serverAddress.openConnection();
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/x-java-serialized-object");
return conn;
}
private void sendRecievedata(GameInfo info) {
try {
URLConnection c = this.getConnection();
OutputStream os = c.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(os);
oos.writeObject(info);
oos.close();
} catch (Exception ex) {
ex.printStackTrace();
}
}
这是servlet代码
try {
HttpSession s = request.getSession(true);
response.setContentType("application/x-java-serialized-object");
InputStream in = request.getInputStream();
ObjectInputStream ois = new ObjectInputStream(in);
GameInfo info = (GameInfo) ois.readObject();
if (info.getUserId() > 0) {
Scores score = new Scores();
score.submitScore(info);
}
} catch (Exception ex) {
ex.printStackTrace();
} finally {
}
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter();
try {
out.println("<html>");
out.println("<head>");
out.println("<title>Servlet submitScore</title>");
out.println("</head>");
out.println("<body>");
out.println("<h1>Servlet submitScore at " + request.getContextPath() + "</h1>");
out.println("</body>");
out.println("</html>");
} catch {
ex.printStackTrace();
} finally {
out.close();
}
现在,我已经尝试通过浏览器访问servlet,只是为了确保地址正确(正确),但是由于某些原因,当我尝试从applet本身访问该地址时,它无法连接。 (调试器甚至无法启动)。
(根据建议,将ex.printStackTrace();添加到每个尝试的捕获中,但是我不知道该在哪里寻找它)
调用该applet的代码看起来与此类似: http : //roseindia.net/jsp/simple-jsp-example/applet-in-jsp.shtml
<jsp:plugin code="Pong.class" name="Games/Pong/Pong" type="applet" width="800" height="600">
<jsp:params>
<jsp:param name="userId" value="<%= user.getUserId()%>" ></jsp:param>
</jsp:params>
</jsp:plugin>
我在这里有什么要注意的吗?
我设法使它起作用。
这是小程序的代码:
private URLConnection getServletConnection()
throws MalformedURLException, IOException {
URL urlServlet = new URL("http://localhost:8080/GamePortal/submitScore");
URLConnection con = urlServlet.openConnection();
con.setDoOutput(true);
con.setRequestProperty(
"Content-Type",
"application/x-java-serialized-object");
return con;
}
private void onSendData(GameInfo info) {
try {
// send data to the servlet
URLConnection con = getServletConnection();
OutputStream outstream = con.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(outstream);
oos.writeObject(info);
oos.flush();
oos.close();
// receive result from servlet
InputStream instr = con.getInputStream();
ObjectInputStream inputFromServlet = new ObjectInputStream(instr);
String result = (String) inputFromServlet.readObject();
//JOptionPane.showMessageDialog(null, result);
inputFromServlet.close();
instr.close();
} catch (Exception ex) {
ex.printStackTrace();
}
}
这是servlet的代码:
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
try {
response.setContentType("application/x-java-serialized-object");
// read a String-object from applet
// instead of a String-object, you can transmit any object, which
// is known to the servlet and to the applet
InputStream in = request.getInputStream();
ObjectInputStream inputFromApplet = new ObjectInputStream(in);
GameInfo score = (GameInfo) inputFromApplet.readObject();
System.out.println(score.getScore());
GameInfo info = score;
if (info.getUserId() > 0) {
Scores instance = new Scores();
instance.submitScore(info);
}
OutputStream outstr = response.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(outstr);
oos.writeObject("reply");
oos.flush();
oos.close();
} catch (ClassNotFoundException ex) {
}
}
感谢您的帮助,请原谅我花太长时间回复。
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