汇编语言问题…以及如何换行？

Question

我开始学习汇编语言。 我需要做的程序非常简单。 1-读取一个4位数的数字（可以是负数）2-输出输入的数字的数字3-计算/输出输入的数字的一半4-计算/输出输入的数字的两倍

所以...这是代码...首先是数据部分

section .data ; Data segment
    msgPrompt       db 'Please enter a number ' ; Ask the user to enter a number
    lenMsgPrompt    equ $-msgPrompt          ; The length of the message
    msgNumber       db 'The entered number is '
    lenMsgNumber    equ $-msgNumber                 
    msgHalf         db 'The half of the entered number is '
    lenMsgHalf      equ $-msgHalf
    msgDouble       db 'The double of the entered numbered is '
    lenMsgDouble    equ $-msgDouble

然后是未初始化的数据（供用户输入）

section .bss        ; Uninitialized data
    userNumber    resb 5
    halfNumber    resb 5
    doubleNumber  resb 5

然后...代码段...

    section .text       ; Code Segment

       global _start
       _start:

       ;Prompt the user
       mov eax, 4
       mov ebx, 1
       mov ecx, msgPrompt
       mov edx, lenMsgPrompt
       int 80h

       ; Read and store the user input
       mov eax, 3
       mov ebx, 2
       mov ecx, userNumber  
       mov edx, 5       ; 5 bytes (numeric, 1 for sign) of that information
       int 80h

       ; Output the message 'The entered number is '
       mov eax, 4
       mov ebx, 1
       mov ecx, msgNumber
       mov edx, lenMsgNumber
       int 80h  

       ; Output the number entered
       mov eax, 4
       mov ebx, 1
       mov ecx, userNumber
       mov edx, 5
       int 80h  

       ; Output the message 'The half of the entered number is '
       mov eax, 4   
       mov ebx, 1
       mov ecx, msgHalf
       mov edx, lenMsgHalf
       int 80h

       ; Calculate the half of the number entered
       mov eax, [userNumber]
       shr eax, 1       ; Shift to the right by one bit
       mov [halfNumber], eax

       ; Output half of the number entered
       mov eax, 4
       mov ebx, 1
       mov ecx, halfNumber
       mov edx, 5
       int 80h

       ; Output the message 'The double of the entered numbered is '
       mov eax, 4
       mov ebx, 1
       mov ecx, msgDouble
       mov edx, lenMsgDouble
       int 80h

       ; Calculate the double of the number entered
       mov ebx, [userNumber]
       shl ebx, 1       ; Shift the the left by one bit
       mov [doubleNumber], ebx

       ; Output double of the number entered
       mov eax, 4
       mov ebx, 1
       mov ecx, doubleNumber
       mov edx, 5
       int 80h

       ; Leave program
       mov eax, 1
       mov ebx, 0
       int 0x80

这是最终结果... 这里 （我没有足够的声誉来发布图像...）

如您所见，这是有问题的...另外，我想在“数字的一半是xxxxx”之后添加新行。

谢谢

Answer 1

看起来您正在对数字的ASCII代码而不是数字值进行算术运算。

Answer 2

您是否缺少EOL代码（13、10）？

msgHalf         db 'The half of the entered number is ', 13, 10