DATEDIFF舍入到最接近的30分钟

Question

我正在使用datediff来获取两个日期时间之间的差异：

DATEDIFF(hh, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), 
   CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS [Hours TurnAround]

我不明白我从该语句中得到的行为，但是我需要的是>= :30, round up, if not, round down,任何内容>= :30, round up, if not, round down,

问题我如何在少于30分钟的时间内将其四舍五入，而在大于或等于30分钟的时间内如何将其四舍五入？

Answer 1

您应该以分钟为单位计算DATEDIFF并进行ROUND然后：

ROUND(CAST(DATEDIFF(MINUTES, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
                      + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
                      + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS FLOAT)/60,0)  AS [Hours TurnAround]