DATEDIFF舍入到最接近的30分鍾

Question

我正在使用datediff來獲取兩個日期時間之間的差異：

DATEDIFF(hh, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), 
   CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS [Hours TurnAround]

我不明白我從該語句中得到的行為，但是我需要的是>= :30, round up, if not, round down,任何內容>= :30, round up, if not, round down,

問題我如何在少於30分鍾的時間內將其四舍五入，而在大於或等於30分鍾的時間內如何將其四舍五入？

Answer 1

您應該以分鍾為單位計算DATEDIFF並進行ROUND然后：

ROUND(CAST(DATEDIFF(MINUTES, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
                      + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
                      + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS FLOAT)/60,0)  AS [Hours TurnAround]