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[英]How to select a row(s) from dynamic table using checkbox (PHP) and insert those row to send mail function
[英]How to select a row(s) from mysql table using checkbox (PHP)
嗨,我有一个页面,显示我的桌子的所有内容。 沿着表的每一行,我还有一列包含一个复选框。 当用户通过选中复选框并按提交按钮选择一个或多个行时,我只希望这些行出现在下一页的表中(buy.php)。 我知道基本上是选择的每行一条select语句。 但我不知道该如何处理。 有人可以帮忙吗? 谢谢
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Shopping</title>
</head>
<body>
<form action='buy.php' method='post'>
<input type='submit' value='Submit' />
</form>
<h1>Buy</h1>
<?php // Script 12.7 - sopping.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
$query = 'SELECT * FROM Items';
if ($r = mysql_query($query, $db)) {
print "<form>
<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
<td><input type='checkbox' name='buy[{$row['ID']}] value='buy' /></td>
</tr>";
}
print "</table>
</form>";
} else {
print '<p style="color: blue">Error!</p>';
}
mysql_close($db); // Close the connection.
?>
</body>
</html>
编辑:我尝试了下面的建议,但我没有桌子。 仅出现页面标题:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Confirmation</title>
</head>
<body>
<h1>Order Details</h1>
<?php // Script 12.7 - buy.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
foreach($_POST['buy'] as $item) {
$query = 'SELECT * FROM Items WHERE ID = $item';
if ($r = mysql_query($query, $db)) {
print "<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
</tr>";
}
print "</table>";
} else {
print '<p style="color: blue">Error!</p>';
}
}
mysql_close($db);
?>
</body>
</html>
您需要创建一个动态SQL查询。
1)我建议您将复选框更改为以下内容
<input type='checkbox' name='buy[]' value='{$row['ID']}' />
2)遍历所有购买选项
<?php
foreach($_POST['buy'] as $item) {
// Append the ID (in the $item variable) to the SQL query, using WHERE `ID` = $item OR `ID` = $item and so on
}
?>
更新:
<?php // Script 12.7 - buy.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
$query = 'SELECT * FROM Items WHERE ';
$item_count = count($_POST['buy']);
for($i = 0; $i < $item_count; $i++) {
$itemid = (int)mysql_real_escape_string($_POST['buy'][i]); // Secures It
$query .= '`ID` = '.$itemid;
if($i +1 < $item_count) {
$query .= ' OR ';
}
}
if ($r = mysql_query($query, $db)) {
print "<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
</tr>";
}
print "</table>";
mysql_close($db);
?>
// this checkbox use
<input type='checkbox' name='buy[]' value='{$row['ID']}' />
//buy.php
foreach($_POST['buy'] as $item) {
$query = "SELECT * FROM Items WHERE ID = $item";
//use " "
// try it if any problem please carefully look you database table
// download file and try it 2file with table sql data
// https://copy.com/8ZsBAFj7LvypLJkK
//此复选框的使用
//buy.php foreach($ _ POST ['buy'] as $ item){
$ query =“选择*来自项目的ID = $ item的项目”; //采用 ” ”
//如果有问题请尝试一下,请仔细查看数据库表//下载文件并尝试使用表sql数据2file
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