How to select a row(s) from mysql table using checkbox (PHP)
Question
Hi I have a page that displays all of the contents of my table. Alongisde each row of the table I also have a column containing a checkbox. When the user selects one or more rows by ticking the checkbox and pressing the submit button, I want just those rows to appear in a table on the next page (buy.php). I know it is basically a select statement per row that is selected. But I dont know how to approach this. Can anybody help? Thanks
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Shopping</title>
</head>
<body>
<form action='buy.php' method='post'>
<input type='submit' value='Submit' />
</form>
<h1>Buy</h1>
<?php // Script 12.7 - sopping.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
$query = 'SELECT * FROM Items';
if ($r = mysql_query($query, $db)) {
print "<form>
<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
<td><input type='checkbox' name='buy[{$row['ID']}] value='buy' /></td>
</tr>";
}
print "</table>
</form>";
} else {
print '<p style="color: blue">Error!</p>';
}
mysql_close($db); // Close the connection.
?>
</body>
</html>
EDIT: I tried the suggestion below and I did not get a table. Just the title of the page appeard:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Confirmation</title>
</head>
<body>
<h1>Order Details</h1>
<?php // Script 12.7 - buy.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
foreach($_POST['buy'] as $item) {
$query = 'SELECT * FROM Items WHERE ID = $item';
if ($r = mysql_query($query, $db)) {
print "<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
</tr>";
}
print "</table>";
} else {
print '<p style="color: blue">Error!</p>';
}
}
mysql_close($db);
?>
</body>
</html>
3 answers
solution1
6 2012-03-31 12:30:09
You need to create a dynamic SQL query.
1) I suggest you change your checkbox to the following
<input type='checkbox' name='buy[]' value='{$row['ID']}' />
2) Loop through all of the buy options
<?php
foreach($_POST['buy'] as $item) {
// Append the ID (in the $item variable) to the SQL query, using WHERE `ID` = $item OR `ID` = $item and so on
}
?>
UPDATE:
<?php // Script 12.7 - buy.php
$db = mysql_connect('localhost', '#####', '#####');
mysql_select_db('shopping', $db);
$query = 'SELECT * FROM Items WHERE ';
$item_count = count($_POST['buy']);
for($i = 0; $i < $item_count; $i++) {
$itemid = (int)mysql_real_escape_string($_POST['buy'][i]); // Secures It
$query .= '`ID` = '.$itemid;
if($i +1 < $item_count) {
$query .= ' OR ';
}
}
if ($r = mysql_query($query, $db)) {
print "<table>";
while ($row = mysql_fetch_array($r)) {
print
"<tr>
<td>{$row['ID']}</td>
<td>{$row['Name']}</td>
<td>{$row['Cost']}</td>
</tr>";
}
print "</table>";
mysql_close($db);
?>
solution2
0 2015-05-15 12:26:55
// this checkbox use
<input type='checkbox' name='buy[]' value='{$row['ID']}' />
//buy.php
foreach($_POST['buy'] as $item) {
$query = "SELECT * FROM Items WHERE ID = $item";
//use " "
// try it if any problem please carefully look you database table
// download file and try it 2file with table sql data
// https://copy.com/8ZsBAFj7LvypLJkK
solution3
0 2015-05-15 12:34:28
// this checkbox use
//buy.php foreach($_POST['buy'] as $item) {
$query = "SELECT * FROM Items WHERE ID = $item"; //use " "
// try it if any problem please carefully look you database table // download file and try it 2file with table sql data
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