如何从红宝石的哈希数组中获取键/值对？

Question

我有一系列哈希（或者至少我认为它们是哈希），我需要为每个哈希提取ID。 我确信ruby有一些快速的方法可以做到这一点...我只是想不通。

我不想遍历数组并构建一个新数组。

[
  [
    {
      "bio": "I am a tech geek who loves starting up companies. While I was in college, I founded Squeeze My Tees",
      "business_name": "Rounded Development",
      "city": "",
      "created_at": "2012-04-22T18:07:44Z",
      "first_name": "Brian",
      "id": 1,
      "industry": "Entertainment",
      "last_name": "Weinreich",
      "lat": null
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:35Z",
      "email": "test@jambo.com",
      "first_name": "asdad",
      "id": 2,
      "industry": null,
      "last_name": "ddfs",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:35Z"
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:39Z",
      "email": "tesasdat@jambo.com",
      "first_name": "fdsd",
      "id": 3,
      "industry": null,
      "last_name": "asdgw",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:39Z"
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:44Z",
      "email": "asdsad@jambo.com",
      "first_name": "ewtrwef",
      "id": 4,
      "industry": null,
      "last_name": "dfd",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:44Z"
    }
  ]
]

Answer 1

要仅提取ID，您可以执行以下操作：

the_IDs = array_of_hashes.collect { |single_array| single_array["id"] }

显然，您可以使用较少的冗长的变量名，它们只是用于说明。 但想法是，您可以遍历数组并收集块返回的任何内容。 在这种情况下，您将不断返回ID， the_IDs将只是所收集内容的数组。