[英]how to produce a nested list from two lists in python
我是python的新手,我有两个清单:
l1 = ['a','b','c','d']
l2 = ['new']
我想要这样的新清单
l3 = [('a','new'),('b','new'),('c','new'),('d','new')]
合并两个列表的最佳方法是什么?
>>> from itertools import product
>>> l1 = ['a','b','c','d']
>>> l2 = ['new']
>>> list(product(l1,l2))
[('a', 'new'), ('b', 'new'), ('c', 'new'), ('d', 'new')]
如果l2
总是只有一个元素,则无需使事情复杂化
l3 = [(x, l2[0]) for x in l1]
请参阅itertools文档 。
特别是,将乘积用于笛卡尔乘积:
from itertools import product:
l1 = ['a','b','c','d']
l2 = ['new']
# Cast to list for l3 to be a list since product returns a generator
l3 = list(product(l1, l2))
>>> from itertools import repeat
>>> l1 = ['a','b','c','d']
>>> l2 = ['new']
>>> zip(l1,repeat(*l2))
[('a', 'new'), ('b', 'new'), ('c', 'new'), ('d', 'new')]
您可以简单地使用列表推导,而无需任何功能:
l3 = [对于l1中的x对于l2中的y为((x,y)]
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