将多行输入存储到字符串中 (Python)

Question

输入：

359716482
867345912
413928675
398574126
546281739
172639548
984163257
621857394
735492861

我的代码：

print("Enter the array:\n")   
userInput = input().splitlines()
print(userInput)

我的问题是， userInput只接受第一行值，但似乎没有接受第一行之后的值？

Answer 1

您可以使用文件对象的readlines()方法：

import sys
userInput = sys.stdin.readlines()

Answer 2

您可以使用生成器轻松创建一个。 这是一个这样的实现。 请注意，您可以按空白返回或任何键盘中断来跳出输入循环

>>> def multi_input():
    try:
        while True:
            data=raw_input()
            if not data: break
            yield data
    except KeyboardInterrupt:
        return


>>> userInput = list(multi_input())
359716482
867345912
413928675
398574126

>>> userInput
['359716482', '867345912', '413928675', '398574126']
>>> 

Answer 3

每个input()只接受一行。 围绕这个的策略：

• 您可以在循环中重复调用input()直到它收到一个空行
• 您可以在循环中重复调用input()直到用户在类 UNIX 操作系统上执行 ctrl-D ，此时将引发 EOFError ，您可以捕获
• 从文本文件或其他比标准输入更合适的来源读取数据

Answer 4

你好呀，

您可以尝试我根据您的要求制定的这种方法。 我在代码上添加了一些注释来解释我想要实现的目标。 很高兴有机会学习一些 Python 代码，我是这门语言的新手，但我非常喜欢它！

def multi_input():
    try:
        #This list will hold all inputs made during the loop
        lst_words = []
        # We will store the final string results on this variable
        final_str ='' 
        #Let's ask first the user to enter the amount of fruits
        print("Please Type in your List of Fruits. \n Press << Enter >> to finish the list:")
        
        #Loop to get as many words as needed in that list
        while True:
            #Capture each word o'er here, pals!
            wrd = input()
            # If word is empty, meaning user hit ENTER, let's break this routine
            if not wrd: break
            # if not, we keep adding this input to the current list of fruits
            else:
                lst_words.append(wrd)

#What if ther user press the interruption shortcut? ctrl+D or Linus or MacOS equivalent?
    except KeyboardInterrupt:
        print("program was manually terminated by the user.")
        return
#the time has come for us to display the results on the screen
    finally:
        #If the list has at least one element, let us print it on the screen
        if(len(lst_words)>0):
            #Before printing this list, let's create the final string based on the elements of the list
            final_str = '\n'.join(lst_words)
            print('You entered the below fruits:')
            print(final_str)
        else:
            quit
#let us test this function now! Happy python coding, folks!
multi_input()

Answer 5

lines = []
while True:
s =input("Enter the string or press ENTER for Output: ")
if s:
    lines.append(s)
else:
    break;

print("OUTPUT: ")
for i in lines:
print (i)

Input:
359716482
867345912
413928675
398574126
546281739
172639548
984163257
621857394
735492861

Output:
359716482
867345912
413928675
398574126
546281739
172639548
984163257
621857394
735492861