[英]looping through a dictionary and printing it in a certain format
我有以下字典:
# a small DB of people who stole my books
dic = {
'Cohen' : 'Calvino' 'Evertt' 'Borges',
'Larry' : 'The Bible',
'Volanski' : 'Phone Book'
}
# here's an abortive attempt to print it in a CSV format
for k in dic.keys():
print (k, '\t')
for v in dic.keys():
print (dic[v], ' ')
这是丑陋的输出:
Volanski
Phone Book
CalvinoEverttBorges
The Bible
Cohen
Phone Book
CalvinoEverttBorges
The Bible
Larry
Phone Book
CalvinoEverttBorges
The Bible
这就是我希望输出看起来像:
Cohen Larry Volanski
Calvino The Bible Phone Book
Evertt
Borgest
(只有标签分隔,我没有在这里显示)
dic = {
'Cohen' : ['Calvino', 'Evertt', 'Borges'],
'Larry' : ['The Bible'],
'Volanski' : ['Phone Book']
}
ordered = []
maxlen = 0
for k in sorted(dic.keys()):
lst = [k] + dic[k]
maxlen = max(len(lst), maxlen)
ordered.append(iter(lst))
for i in range(maxlen):
print "\t".join(next(j, '') for j in ordered)
你可以制定整洁的格式
dic = {'Cohen' : ['Calvino', 'Evertt', 'Borges'],
'Larry' : ['The Bible'],
'Volanski' : ['Phone Book']}
# Get max name size
mx_nm_len = len(max(dic,key=len))
mx_bk_len = max([len(max(books, key=len)) for books in dic.itervalues()])
# Store max name size + 1
mx = max([mx_nm_len, mx_bk_len]) + 1
# Store people
keys = dic.keys()
# Create generic format code to print neat list
fmat = ("%-"+str(mx)+"s")*len(keys)
# Print header line
print fmat % tuple(keys)
# similar to zip command but works for any number of lists
# Assumes all dic.values() are lists
# "zips" to longest list and uses None when any given list runs out of values
books = map(None, *dic.values())
# replaces None values in row outputs with empty strings and prints result using
# string format code (fmat)
for row in books:
row = tuple([book if book!= None else "" for book in row])
print fmat % row
关键是你没有以正确的方式定义数据。 Python定义第一个条目的方式与它的打印方式完全一致:单个字符串。 如果需要多个元素,则需要将元素定义为包含多个元素:
dic = {
'Cohen' : ['Calvino', 'Evertt', 'Borges'],
'Larry' : ['The Bible'],
'Volanski' : ['Phone Book']
}
现在你可以简单地这样做:
for key, value in dic.items():
print "%s\t%s" % (key, "\t".join(value))
编辑确定,没有看到你想要顶部和标题向下的名称。 有点棘手,但这样做会:
import itertools
print "\t".join(dic.keys())
for books in itertools.izip_longest(*dic.values(), fillvalue=''):
print "\t".join(books)
此解决方案可确保对输出进行排序,并使项目在正确的列中结束。 我使用expandtabs()
来设置标签长度,使其非常漂亮。
import itertools
dic = {'Cohen':['Calvino', 'Evertt','Borges'],'Larry': ['The Bible'], 'Volanski' :['Phone Book']}
sorted_keys = sorted(dic.keys())
for name in sorted_keys:
print (name+'\t').expandtabs(15),
print
zippp = list(itertools.izip_longest(*[dic[i] for i in sorted_keys]))
for i in xrange(len(zippp[0])):
for j in xrange(len(zippp)):
if zippp[i][j]:
print (zippp[i][j]+'\t').expandtabs(15),
print
生产:
Cohen Larry Volanski
Calvino The Bible Phone Book
Evertt
Borges
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