[英]How to upload a file using Apache Commons file upload from a servlet?
我需要从服务器端上传xml文件,其中文件的内容在字符串中。 如何使该文件内容上载(基本上保存)在服务器上?
这是我正在尝试的方法,如果我直接将文件提供给FileBody
但又如何欺骗它使文件内容作为多部分请求进入另一个servlet,则可以正常工作?
private def createConfiguration(def sessiontoken)
{
def xmlString=""
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httppost = new HttpPost(fileParams.create);
//FileBody bin = new FileBody(new File("C:\\Simon\\myxml.xml"));
StringBody st = new StringBody(sessiontoken);
StringBody cfgname = new StringBody(reqParams.c_Cfgname[0]);
StringBody cfgdesc = new StringBody(reqParams.c_Cfgdesc[0]);
StringBody cfgtype = new StringBody(reqParams.c_Cfgtype[0]);
StringBody cfgfile = new StringBody(reqParams.CFGFILE[0]);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("sessiontoken", st);
reqEntity.addPart("cfgname", cfgname);
reqEntity.addPart("cfgdesc", cfgdesc);
reqEntity.addPart("cfgenv", cfgtype);
//reqEntity.addPart("cfgfile", bin);
reqEntity.addPart("cfgfile", cfgfile);
httppost.setEntity(reqEntity);
System.out.println("executing request " + httppost.getRequestLine());
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
System.out.println("----------------------------------------");
//System.out.println(response.getStatusLine());
if (resEntity != null) {
//System.out.println("Response content length: " + resEntity.getContentLength());
xmlString=resEntity.getContent().getText()
}
EntityUtils.consume(resEntity);
} finally {
try { httpclient.getConnectionManager().shutdown(); } catch (Exception ignore) {}
}
xmlString
}
如果使用上面的代码,则会出现以下异常
----------------------------------------
Exception while processing your Request.
No result defined for action com.abc.dc.actions.CreateConfiguration and
result input
更新资料
因此,现在在检查了tomcat日志和其他服务器端代码之后,我知道内部dc
正在获取cfgfile
并将其设置为
public void setCfgfile(File cfgfile)
{
this.cfgfile = cfgfile
}
这给了我
java.lang.NoSuchMethodException: com.abc.dc.actions.CreateConfiguration.setCfgfile([Ljava.lang.String;)
那么如何在public void setCfgfile(String cfgfile)
重载setCfgfile
方法并将cfgfile
转换为File
对象呢?
甚至更好
如何将此cfgfile
字符串变量转换为FileBody
对象?
最后,这就是我的工作方式:)
private def sendRequest(def sessiontoken,def sendUrl)
{
logger.debug("Inside sendRequest to: "+sendUrl)
def xmlString=""
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httppost = new HttpPost(sendUrl);
def filename=reqParams.filename
logger.debug("Filename: "+filename)
FileBody bin = new FileBody(writeToFile(filename,reqParams.cfgfile));
StringBody st = new StringBody(sessiontoken);
StringBody cfgid=new StringBody("")
if(reqParams.containsKey('cfgfile')&&reqParams.cfgid!=null)
{
cfgid= new StringBody(reqParams.cfgid);
}
StringBody cfgname = new StringBody(reqParams.cfgname);
StringBody cfgdesc = new StringBody(reqParams.cfgdesc);
StringBody cfgenv = new StringBody(reqParams.cfgenv);
logger.debug("attaching multipart")
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("sessiontoken", st);
reqEntity.addPart("cfgid", cfgid);
reqEntity.addPart("cfgname", cfgname);
reqEntity.addPart("cfgdesc", cfgdesc);
reqEntity.addPart("cfgenv", cfgenv);
reqEntity.addPart("cfgfile", bin);
httppost.setEntity(reqEntity);
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
if (resEntity != null) {
xmlString=resEntity.getContent().getText()
}
EntityUtils.consume(resEntity);
} finally {
try { httpclient.getConnectionManager().shutdown(); } catch (Exception ignore) {}
}
xmlString
}
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