[英]How to upload a file using Apache Commons file upload from a servlet?
我需要從服務器端上傳xml文件,其中文件的內容在字符串中。 如何使該文件內容上載(基本上保存)在服務器上?
這是我正在嘗試的方法,如果我直接將文件提供給FileBody
但又如何欺騙它使文件內容作為多部分請求進入另一個servlet,則可以正常工作?
private def createConfiguration(def sessiontoken)
{
def xmlString=""
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httppost = new HttpPost(fileParams.create);
//FileBody bin = new FileBody(new File("C:\\Simon\\myxml.xml"));
StringBody st = new StringBody(sessiontoken);
StringBody cfgname = new StringBody(reqParams.c_Cfgname[0]);
StringBody cfgdesc = new StringBody(reqParams.c_Cfgdesc[0]);
StringBody cfgtype = new StringBody(reqParams.c_Cfgtype[0]);
StringBody cfgfile = new StringBody(reqParams.CFGFILE[0]);
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("sessiontoken", st);
reqEntity.addPart("cfgname", cfgname);
reqEntity.addPart("cfgdesc", cfgdesc);
reqEntity.addPart("cfgenv", cfgtype);
//reqEntity.addPart("cfgfile", bin);
reqEntity.addPart("cfgfile", cfgfile);
httppost.setEntity(reqEntity);
System.out.println("executing request " + httppost.getRequestLine());
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
System.out.println("----------------------------------------");
//System.out.println(response.getStatusLine());
if (resEntity != null) {
//System.out.println("Response content length: " + resEntity.getContentLength());
xmlString=resEntity.getContent().getText()
}
EntityUtils.consume(resEntity);
} finally {
try { httpclient.getConnectionManager().shutdown(); } catch (Exception ignore) {}
}
xmlString
}
如果使用上面的代碼,則會出現以下異常
----------------------------------------
Exception while processing your Request.
No result defined for action com.abc.dc.actions.CreateConfiguration and
result input
更新資料
因此,現在在檢查了tomcat日志和其他服務器端代碼之后,我知道內部dc
正在獲取cfgfile
並將其設置為
public void setCfgfile(File cfgfile)
{
this.cfgfile = cfgfile
}
這給了我
java.lang.NoSuchMethodException: com.abc.dc.actions.CreateConfiguration.setCfgfile([Ljava.lang.String;)
那么如何在public void setCfgfile(String cfgfile)
重載setCfgfile
方法並將cfgfile
轉換為File
對象呢?
甚至更好
如何將此cfgfile
字符串變量轉換為FileBody
對象?
最后,這就是我的工作方式:)
private def sendRequest(def sessiontoken,def sendUrl)
{
logger.debug("Inside sendRequest to: "+sendUrl)
def xmlString=""
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httppost = new HttpPost(sendUrl);
def filename=reqParams.filename
logger.debug("Filename: "+filename)
FileBody bin = new FileBody(writeToFile(filename,reqParams.cfgfile));
StringBody st = new StringBody(sessiontoken);
StringBody cfgid=new StringBody("")
if(reqParams.containsKey('cfgfile')&&reqParams.cfgid!=null)
{
cfgid= new StringBody(reqParams.cfgid);
}
StringBody cfgname = new StringBody(reqParams.cfgname);
StringBody cfgdesc = new StringBody(reqParams.cfgdesc);
StringBody cfgenv = new StringBody(reqParams.cfgenv);
logger.debug("attaching multipart")
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("sessiontoken", st);
reqEntity.addPart("cfgid", cfgid);
reqEntity.addPart("cfgname", cfgname);
reqEntity.addPart("cfgdesc", cfgdesc);
reqEntity.addPart("cfgenv", cfgenv);
reqEntity.addPart("cfgfile", bin);
httppost.setEntity(reqEntity);
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
if (resEntity != null) {
xmlString=resEntity.getContent().getText()
}
EntityUtils.consume(resEntity);
} finally {
try { httpclient.getConnectionManager().shutdown(); } catch (Exception ignore) {}
}
xmlString
}
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