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使用urlopen.read中的“byte-like object”和JSON?

[英]Use “byte-like object” from urlopen.read with JSON?

只是试图测试非常简单的Python JSON命令,但我遇到了一些麻烦。

urlopen('http://www.similarsitesearch.com/api/similar/ebay.com').read()

应该输出

'{"num":20,"status":"ok","r0":"http:\\/\\/www.propertyroom.com\\/","r1":"http:\\/\\/www.ubid.com\\/","r2":"http:\\/\\/www.bidcactus.com\\/","r3":"http:\\/\\/www.etsy.com\\/","r4":"http:\\/\\/us.ebid.net\\/","r5":"http:\\/\\/www.bidrivals.com\\/","r6":"http:\\/\\/www.ioffer.com\\/","r7":"http:\\/\\/www.shopgoodwill.com\\/","r8":"http:\\/\\/www.beezid.com\\/","r9":"http:\\/\\/www.webidz.com\\/","r10":"http:\\/\\/www.auctionzip.com\\/","r11":"http:\\/\\/www.overstock.com\\/","r12":"http:\\/\\/www.bidspotter.com\\/","r13":"http:\\/\\/www.paypal.com\\/","r14":"http:\\/\\/www.ha.com\\/","r15":"http:\\/\\/www.onlineauction.com\\/","r16":"http:\\/\\/bidz.com\\/","r17":"http:\\/\\/www.epier.com\\/","r18":"http:\\/\\/www.sell.com\\/","r19":"http:\\/\\/www.rasmus.com\\/"}'

但我得到同样的字符串,前面有一个b

b'{"num":20,"status":"ok","r0":"http:\\/\\/www.propertyroom.com\\/","r1":"http:\\/\\/www.ubid.com\\/","r2":"http:\\/\\/www.bidcactus.com\\/","r3":"http:\\/\\/www.etsy.com\\/","r4":"http:\\/\\/us.ebid.net\\/","r5":"http:\\/\\/www.bidrivals.com\\/","r6":"http:\\/\\/www.ioffer.com\\/","r7":"http:\\/\\/www.shopgoodwill.com\\/","r8":"http:\\/\\/www.beezid.com\\/","r9":"http:\\/\\/www.webidz.com\\/","r10":"http:\\/\\/www.auctionzip.com\\/","r11":"http:\\/\\/www.overstock.com\\/","r12":"http:\\/\\/www.bidspotter.com\\/","r13":"http:\\/\\/www.paypal.com\\/","r14":"http:\\/\\/www.ha.com\\/","r15":"http:\\/\\/www.onlineauction.com\\/","r16":"http:\\/\\/bidz.com\\/","r17":"http:\\/\\/www.epier.com\\/","r18":"http:\\/\\/www.sell.com\\/","r19":"http:\\/\\/www.rasmus.com\\/"}'

随后,当我试着跑

json.loads(urlopen('http://similarsitesearch.com/api/similar/ebay.com').read())

它给了我错误信息:

TypeError:不能在类字节对象上使用字符串模式“

我假设与b

我从urllib.request导入了urlopen ,我正在运行Python 3。

有任何想法吗?

read()中的内容是字节类型,因此您需要在尝试将其解码为json对象之前将其转换为字符串。

要将字节转换为字符串,请将代码更改为: urlopen('http://similarsitesearch.com/api/similar/ebay.com').read().decode("utf-8")

它工作得很好:

def myView(request):
    encoding = request.read().decode("utf-8")
    dic = json.loads(encoding)
    print(dic)

您需要检查Content-Type标头中指定的字符集,并在将其传递给json.load*()之前对其进行解码。

urllib返回一个字节数组,我假设它是py3中的默认值,json期待一个字符串。 尝试在调用json调用之前将返回值包装在str()调用中

j = str(urlopen('http://similarsitesearch.com/api/similar/ebay.com').read())
json.loads(j)

看起来像字节文字 研究如何使用http获取数据,或者API如何返回标头中的数据。

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