Backbone.js - 集合未定义

Question

我正在尝试学习backbone.js，但我仍然坚持抓取json并添加到集合中。集合未定义，我不知道为什么。 码：

$(document).ready(function() {
    (function($) {
        //model
        window.Wine = Backbone.Model.extend();

        window.WineCollection = Backbone.Model.extend({
            url: "http://localhost/bootstrap/json.php",
            model: Wine
        });


        //views
        window.WineItemView = Backbone.View.extend({
            template: _.template($("#wine-item-template").html()),
            tagName: 'li',
            render: function() {
                $(this.el).html(this.template(this.model.toJSON()));
                return this;
            }
        });

        window.WineListView = Backbone.View.extend({
            tagName: 'ul',
            initialize: function() {
                this.model.bind('reset', this.render, this);

            },
            render: function() {

                _.each(this.model.models, function(wine) {
                    $(this.el).append(new WineItemView({
                        model: wine
                    }).render().el);
                }, this);
                return this;
            }
        });


        window.WineView = Backbone.View.extend({
            template: _.template($('#wine-template').html()),
            render: function() {
                $(this.el).html(this.template(this.model.toJSON()));
                return this;
            }
        });
        //Router
        window.AppRouter = Backbone.Router.extend({
            routes: {
                '': 'home',
                'wines/:id': "wineDetails"
            },
            home: function() {
                this.wineList = new WineCollection();

                this.wineListV = new WineListView({
                    model: this.wineList
                });
                this.wineList.fetch({success: function(){
                    console.log(this.wineList.models); // => 2 (collection have been populated)
                }});
                console.log(this.wineListV);

                $("#winelist").html(this.wineListV.render().el);
            },
            wineDetails: function(id) {
                this.wine = this.wineList.get(id);
                console.log(id);
                this.wineView = new WineView({
                    model: this.wine
                });
                $("#container").empty().html(this.wineView.render().el);
            }
        });


    })(jQuery);

    var app = new AppRouter();
    Backbone.history.start();
});

json.php返回：

[
   {
      "name":"Wine 1",
      "price":"100",
      "status":"available"
   },
   {
      "name":"Wine 1",
      "price":"100",
      "status":"available"
   },
   {
      "name":"Wine 1",
      "price":"100",
      "status":"available"
   }
]

我在我的localhost上测试它。

Answer 1

你犯了一个愚蠢的错字：

window.WineCollection = Backbone.Model.extend

应该

window.WineCollection = Backbone.Collection.extend

请注意，按照惯例您WineListView类应该使用this.collection引用的实例WineCollection和骨干集合对象提供下划线迭代方法，从而代替

.each(this.model.models, function(wine) {

做

this.collection.each(function (wineModel) {

Answer 2

你应该改变

window.WineCollection = Backbone.Model.extend({
            model: Wine,
            url: "wine.json"

        });

至

window.WineCollection = Backbone.Collection.extend({
            model: Wine,
            url: "wine.json"

        });

Answer 3

欢迎来到SO :)这是你的第一个questoin所以让我让它变得难忘。 当你说集合undefined你可以为我们提供行号（或突出显示它），这样就可以很容易地进行调试。 在initialize方法中你必须把_.bindAll(this)放在你想要引用你想要的对象（默认为window对象）而不是下面做＃1的情况下

 _.each(this.model.models, function (wine) {
     $(this.el).append(new WineItemView({
         model: wine
     }).render().el);
 }, this);

1

 this.model.each(function (wine) {
     $(this.el).append(new WineItemView({
         model: wine
     }).render().el);
 }, this);

试试这个

 window.WineListView = Backbone.View.extend({
     tagName: 'ul',
     initialize: function () {
         _.bindAll(this);
         this.model.on('reset', this.render);
     },
     render: function () {
         #1
     }
 });

万一你丢失了这里是代码http://jsbin.com/axixir/edit#javascript的副本