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[英]Select name, lastname, brand from table where brand is the most voted
[英]SQL to select brand from a table, if another table has a product with that brand
使用MySQL和PHP。
我有两个表产品和库存。
产品具有{productID | 产品| 品牌|}
库存有{ID | storeID | productID | 数量 价钱 }
我需要在特定商店获得所有品牌。
所以这是我无法使用的。
SELECT DISTINCT brand
FROM products
WHERE 'products.productID' = 'stock.productID'
AND 'stock.storeID' = 1
如果删除比较“ WHERE”,它将返回所有品牌。
尝试
Select p.brand FROM products p, stock s
WHERE p.productID=s.productID and s.storeID='1'
SELECT DISTINCT p.brand
FROM products p inner join stock s on p.productID=s.productID
WHERE `stock.storeID` = 1
标记`和'之间的差异
尝试
"SELECT p.* FROM Products p
INNER JOIN stock s USING(productID)
WHERE s.storeID = '".(int)$givenID."'
GROUP BY p.brand";
我们也可以这样写
SELECT DISTINCT p.brand FROM products p , stock s where p.productID=s.productID(+) and stock.storeID = 1
尝试这个:
SELECT DISTINCT p.brand
FROM products p
INNER JOIN stock s
ON p.productID=s.productID
WHERE s.`storeID` = 1
这会有所帮助
select p.brand
from product p, stock s
where p.productID = s.productID
and s.storeID = 1
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