SQL to select brand from a table, if another table has a product with that brand

Question

Using MySQL and PHP.

I have two tables products and stock.

products has { productID | product | brand|}

stock has { ID | storeID | productID | qty | price }

I need to get all of the brands available at a specific store.

So here is what I have that doesn't work.

SELECT DISTINCT brand 
  FROM products 
 WHERE 'products.productID' = 'stock.productID' 
   AND 'stock.storeID' = 1

If I remove the compare "WHERE" it returns all of the brands.

Answer 1

Try

Select p.brand FROM products p, stock s 
WHERE p.productID=s.productID and s.storeID='1'

Answer 2

SELECT DISTINCT p.brand 
FROM products p inner join stock s on p.productID=s.productID
WHERE `stock.storeID` = 1

mark the diff between ` and '

Answer 3

try

 "SELECT p.* FROM Products p 
 INNER JOIN stock s USING(productID)
 WHERE s.storeID = '".(int)$givenID."' 
 GROUP BY p.brand";

Answer 4

我们也可以这样写

SELECT DISTINCT p.brand FROM products p , stock s where  p.productID=s.productID(+) and stock.storeID = 1

Answer 5

Try this:

SELECT DISTINCT p.brand 
FROM   products p 
             INNER JOIN stock s 
                  ON p.productID=s.productID
WHERE s.`storeID` = 1

Answer 6

This will help

select p.brand 
  from product p, stock s 
 where p.productID = s.productID
   and s.storeID = 1