[英]issue with NSOperationQueue, weakSelf and blocks
我有以下代码:
[[AHPinterestAPIClient sharedClient] getPath:requestURLPath parameters:nil
success:^(AFHTTPRequestOperation *operation, id response) {
[weakSelf.backgroundQueue_ addOperationWithBlock:^{
[self doSomeHeavyComputation];
[[NSOperationQueue mainQueue] addOperationWithBlock:^{
[weakSelf.collectionView_ setContentOffset:CGPointMake(0, 0)];
[weakSelf.collectionView_ reloadData];
[weakSelf.progressHUD_ hide:YES];
[[NSNotificationCenter defaultCenter] performSelector:@selector(postNotificationName:object:) withObject:@"UIScrollViewDidStopScrolling" afterDelay:0.3];
[weakSelf.progressHUD_ hide:YES];
}];
}];
}
failure:^(AFHTTPRequestOperation *operation, NSError *error) {
[weakSelf.progressHUD_ hide:YES];
[weakSelf.collectionView_.pullToRefreshView stopAnimating];
NSLog(@"Error fetching user data!");
NSLog(@"%@", error);
}];
出于某种原因,这在iOS 5中可以正常工作,但在iOS 6中则无法工作(崩溃)。 现在,我不再要问有关iOS 6的问题,因为它仍处于NDA之下。 我想知道的是,以上代码是否错误? 如果是,我该如何解决。
如果我将代码放在mainQueue之外的块中,那就很好。 我要在这里做的是仅在[self doSomeHeavyComputation]完成后再执行NSOperationQueue mainQueue。 所以这是一个依赖关系,我应该如何添加这个依赖关系?
更新:
如果有帮助,请查看崩溃日志:
建议在区块中“展开”弱引用,因此请尝试以下操作:
__weak id weakSelf = self;
[client getPath:path parameters:nil success:^(id op, id response) {
id strongSelf = weakSelf;
if (strongSelf == nil) return;
__weak id internalWeakSelf = strongSelf;
[strongSelf.backgroundQueue_ addOperationWithBlock:^{
id internalStrongSelf = internalWeakSelf;
if (internalStrongSelf == nil) return;
[internalStrongSelf doSomeHeavyComputation];
__weak id internalInternalWeakSelf = internalStrongSelf;
[[NSOperationQueue mainQueue] addOperationWithBlock:^{
id internalInternalStrongSelf = internalInternalWeakSelf;
if (internalInternalStrongSelf == nil) return;
[internalInternalStrongSelf reloadCollectionView];
}];
}];
}
failure:^(id op, NSError *error) {
id strongSelf = weakSelf;
if (strongSelf == nil) return;
[strongSelf stopProgress];
NSLog(@"Error fetching user data: %@", error);
}];
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.