将ID与不同表行的ID进行比较mysql

Question

因此，我尝试从某人检索所有兴趣，并能够列出它们。 这适用于以下查询。

SELECT *,(
    SELECT GROUP_CONCAT(interest_id SEPARATOR ",")
    FROM people_interests
    WHERE person_id = people.id
) AS interests
FROM people
WHERE id IN (
    SELECT person_id
    FROM people_interests
    WHERE interest_id = '.$site->db->clean($_POST['showinterest_id']).'
)
ORDER BY lastname, firstname

在我遇到的麻烦中，我只想选择那些恰好在表volleyballplayers拥有其ID的用户。 该表仅具有一个id，person_id，team_id和日期字段。

SELECT *,(
    SELECT GROUP_CONCAT(interest_id SEPARATOR ",")
    FROM people_interests
    WHERE person_id = people.id
) AS interests
FROM people
WHERE id IN (
    SELECT person_id
    FROM people_interests
    WHERE volleyballplayers.person_id = person_id
)
ORDER BY lastname, firstname

我只是想确保只显示排球运动员表中的人，但是我得到一个错误，说Unknown column 'volleyballplayers.person_id' in 'where clause'中的Unknown column 'volleyballplayers.person_id' in 'where clause'尽管我非常确定表的名称和我知道该列名为person_id。

Answer 1

尝试通过子查询将其加入，

SELECT  *, GROUP_CONCAT(interest_id) interests
FROM    people a
        INNER JOIN people_interests b
            ON b.person_id = a.id
        INNER JOIN
        (
            SELECT DISTINCT person_id
            FROM volleyballplayers
        ) c ON b.person_id = c.person_id
GROUP BY a.id
ORDER BY lastname, firstname