將ID與不同表行的ID進行比較mysql

Question

因此，我嘗試從某人檢索所有興趣，並能夠列出它們。 這適用於以下查詢。

SELECT *,(
    SELECT GROUP_CONCAT(interest_id SEPARATOR ",")
    FROM people_interests
    WHERE person_id = people.id
) AS interests
FROM people
WHERE id IN (
    SELECT person_id
    FROM people_interests
    WHERE interest_id = '.$site->db->clean($_POST['showinterest_id']).'
)
ORDER BY lastname, firstname

在我遇到的麻煩中，我只想選擇那些恰好在表volleyballplayers擁有其ID的用戶。 該表僅具有一個id，person_id，team_id和日期字段。

SELECT *,(
    SELECT GROUP_CONCAT(interest_id SEPARATOR ",")
    FROM people_interests
    WHERE person_id = people.id
) AS interests
FROM people
WHERE id IN (
    SELECT person_id
    FROM people_interests
    WHERE volleyballplayers.person_id = person_id
)
ORDER BY lastname, firstname

我只是想確保只顯示排球運動員表中的人，但是我得到一個錯誤，說Unknown column 'volleyballplayers.person_id' in 'where clause'中的Unknown column 'volleyballplayers.person_id' in 'where clause'盡管我非常確定表的名稱和我知道該列名為person_id。

Answer 1

嘗試通過子查詢將其加入，

SELECT  *, GROUP_CONCAT(interest_id) interests
FROM    people a
        INNER JOIN people_interests b
            ON b.person_id = a.id
        INNER JOIN
        (
            SELECT DISTINCT person_id
            FROM volleyballplayers
        ) c ON b.person_id = c.person_id
GROUP BY a.id
ORDER BY lastname, firstname