如何解析Json对象

Question

我被困在json对象解析上，真的很努力。 问题是如何解析json对象。 这是我在日志中得到的响应。

{"0":{"**title**":"Test Event","url_title":"test_event1","status":"open","entry_date":"Sep 10, 2012, 

05:20:38AM","entry_id":"26","site_id":"1","channel_id":"3","field_dt_40":null,"field_dt_58":null,"channel_title":"News & 

Events","channel_name":"news_events","start_date":"1348120800","end_date":"1348120800","start_time": "43200","end_time":"46800","where":"FCF","news_event_description":"<p>\n\tLunch with group.<\/p>\n"},

"1":{"**title**":"Test Event 2","url_title":"test_event_2","status":"open","entry_date":"Sep 10, 2012, 05:20:08AM","entry_id":"28","site_id":"1","channel_id":"3","field_dt_40":null,"field_dt_58":null,"channel_title":"News & Events","channel_name":"news_events","start_date":"1348207200","end_date":"1348207200","start_time":"43200","end_time":"46800","where":"FCF - Lunch","news_event_description":"<p>\n\tThis was a great event.<\/p>\n"},

"2":{"**title**":"Test Event 3","url_title":"test_event_3","status":"open","entry_date":"Sep 10, 2012, 05:20:54AM","entry_id":"29","site_id":"1","channel_id":"3","field_dt_40":null,"field_dt_58":null,"channel_title":"News & Events","channel_name":"news_events","start_date":"1346738400","end_date":"1346738400","start_time":"7200","end_time":"11700","where":"FCF - Lunch","news_event_description":"<p>\n\tFall planning season.<\/p>\n"}}

问题是我想在tableview中显示所有标题。 我可以使用键0,1,2获得单个Title。 但是我希望所有的标题在我解析后立即显示

请大家帮帮我，谢谢。

Answer 1

假设jsonDict是您的json字典。

NSArray * keys=[[NSArray alloc]init];
keys=[jsonDict allKeys];
NSMutableArray *titles=[[NSMutableArray alloc]init];
for(int i=0;i<[keys count];i++){
      [titles addObject:[[jsonDict valueForKey:[keys objectAtIndex:i]]valueForKey:@"title"]];
}
NSLog(@"your array of titles : %@",titles); //use this array to fill your cell

Answer 2

您是否尝试自己解析JSON？ 您可能会发现，使用经过良好测试的东西（如TouchJSON或Apple自己的NSJSONSerilization）会更容易。 结果应该是您可以随意使用的Objective-C对象图。

无论如何，您所拥有的相当于字典的字典。 如果您拥有一个称为myJSONDictionary的NSDictionary，则可以说：

NSArray *theObjects = [myJSONDictionary allValues]; // gets all the objects
NSArray *theTitles = [theObjects valueForKey:@"**title**"]; // gets all the titles

您还可以使用快速枚举遍历字典：

NSMutableArray *theTitles = [NSMutableArray array];
for (NSString *key in myJSONDictionary) {
    NSDictionary *object = [myJSONDictionary objectForKey:key];
    NSString *title = [object objectForKey:@"**title**"];
    [theTitles addObject:title]
}

如果只需要标题，那么这样做就没有真正的优势，而不是像第一个示例中那样使用KVC，但是如果您需要为每个对象完成更复杂的工作，那么这可能是正确的选择。