我不了解并且不知道如何解决的ImagePicker IOS错误

Question

我希望用户在按下按钮时通过操作从iPhone中选择一个图像（通过action：buttonClicked），并且希望该图像在我拥有的imageview上查看（imageAddPicture是该图像视图的名称）

我发现了很多信息，但是当我使用此代码时，出现以下错误：

自我，释放，picker.sourceType =（sender == buttonClicked），...

有人能帮助我吗？ （我是stackoverflow.com的新手，但我确实需要帮助，我会尽力帮助其他人）这是我使用的代码：

-(IBAction)buttonClicked:(id)sender
{
    UIImagePickerController *picker = [[UIImagePickerController alloc] init];
    picker.delegate = self;
    picker.allowsImageEditing = YES;
    picker.sourceType = (sender == buttonClicked) ?    UIImagePickerControllerSourceTypeCamera :
    UIImagePickerControllerSourceTypeSavedPhotosAlbum;
    [self presentModalViewController: picker animated:YES];
    [picker release];
}
-(IBAction)selectExitingPicture
{
    if([UIImagePickerController isSourceTypeAvailable:
        UIImagePickerControllerSourceTypePhotoLibrary])
    {
        UIImagePickerController *picker= [[UIImagePickerController alloc]init];
        picker.delegate = self;
        picker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary;
        [self presentModalViewController:picker animated:YES];
        [picker release];
    }
}

-(void)imagePickerController:(UIImagePickerController *)picker
      didFinishPickingImage : (UIImage *)image
                 editingInfo:(NSDictionary *)editingInfo
{
    imageAddPicture.image = image;
    [picker dismissModalViewControllerAnimated:YES];
}
-(void)imagePickerControllerDidCancel:(UIImagePickerController *)  picker
{
    [picker dismissModalViewControllerAnimated:YES];
}

Answer 1

您正在自动引用计数中处理项目。 因此，您无需释放对象。 只需删除此行。 智利:)

picker.sourceType = (sender == buttonClicked) ?    UIImagePickerControllerSourceTypeCamera :
    UIImagePickerControllerSourceTypeSavedPhotosAlbum;

这条线应该是

picker.sourceType = (sender == buttonClicked:) ?    UIImagePickerControllerSourceTypeCamera :
    UIImagePickerControllerSourceTypeSavedPhotosAlbum;