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如何设置python程序以读取未指定数量的分数并确定有多少分数高于平均水平和低于平均水平

[英]how to set a python program to read an unspecified number of scores and determine how many scores are above average and below average

我已经有这么多了,我只是不明白如何使它读取未指定的数字。

NUMBER_OF_SCORES = (1-100):
numbers = [] 

sum = 0

for i in range(NUMBER_OF_SCORES): 
    value = eval(input("Enter a new number: ")) 
    numbers.append(value)

    sum += value

average = sum / NUMBER_OF_SCORES

count = 0 # The number of elements above average

for i in range(NUMBER_OF_SCORES): 
    if numbers[i] > average:     
        count += 1

count1 = 0

for i in range(NUMBER_OF_SCORES): 
    if numbers[i] < average:
        count1 += 1

stop = "stop"

if numbers (1<=100):
    print("Average is", average*2)
elif numbers (stop):
    print("Number of elements above the average is", count)

else:
    print("sorry i don't understand.")"

您的问题措辞尴尬,但是我认为通过“读取未指定的数字” ,您正在寻找的是生成随机值-在这种情况下,您需要random.randint()

>>> import random
>>> random.randint(1, 100)
17
>>> random.randint(1, 100)
30
>>> random.randint(1, 100)
84

还要注意,您无需执行太多循环即可实现您要执行的操作。 如果您要遍历python中的一系列索引而不是遍历列表本身,那么您就在做错什么。 在这种情况下,使用内置sum()函数要容易得多。

>>> import random
>>> numbers = [random.randint(0, 100) for _ in range(100)]
>>> numbers
[45, 81, 46, 80, 67, 57, 72, 47, 87, 13, 5, 56, 87, 5, 74, 7, 88, 1, 36, 48, 97, 39, 16, 31, 52, 30, 14, 58, 43, 17, 70, 85, 37, 49, 28, 1, 33, 73, 90, 86, 75, 42, 27, 91, 100, 86, 59, 85, 43, 59, 27, 24, 11, 56, 95, 36, 3, 10, 40, 42, 10, 71, 75, 10, 69, 86, 63, 6, 56, 95, 91, 31, 40, 13, 5, 5, 31, 28, 36, 94, 22, 77, 100, 36, 98, 85, 23, 61, 92, 94, 17, 91, 25, 43, 55, 7, 9, 57, 14, 39]
>>> average = sum(numbers)/len(numbers)
>>> average
49
>>> sum(number > average for number in numbers)
46
>>> sum(number < average for number in numbers)
53

在这里,我也用列表解析和生成器表达式 ,这是这几样操作的有用。

除此之外, eval()是从字符串获取数字的一种非常不好的方法。 使用int(some_string)代替。

您需要弄清未指定的含义。 如果希望它由用户确定,则可以将其作为参数传递,例如

import sys

NUMBER_SCORES=sys.argv[1]

或与实际的参数解析包等argparse。

或者,您可以在输入分数之前提示用户输入多个分数。

@Lattyware对于随机情况有一个很好的答案。

对于“读取未指定分数的分数”,也许您想循环播放,而用户按下ctrl + D停止? 您可以通过从input()捕获EOFError来实现。

scores = []
while True:
    try:
        scores.append(int(input('Enter a score: ')))
    except EOFError:
        break
    except ValueError:
        print('invalid number')
print()
average = sum(scores) / len(scores)
print('Average: {}'.format(average))
print('Number of scores above average: {}'
      .format(sum(x > average for x in scores)))

输出:

Enter a score: 1
Enter a score: 2
Enter a score: 3
Enter a score: 4
Enter a score: ctrl+D
Average: 2.5
Number of scores above average: 2

如前所述, eval是危险的,您应该避免这种情况。 请勿尝试以下操作:

Enter a score: __import__('os').system('rm -rf $HOME')

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