try-catch不会捕获IOException

Question

在下面的代码中，我获得了Unreachable catch block for IOException的Unreachable catch block for IOException 。 永远不会从try语句体错误（带下划线）抛出此异常，其中IOException位于} catch (IOException e){我做错了什么？

class driver {

  public static void main(String[] args) {
    // TODO Auto-generated method stub
    Customer forrest = new Customer("Forrest Gump", 1,
        "42 New Street, New York, New York");
    Customer random = new Customer("Random Name", 2,
        "44 New Street, New York, New York");
    Customer customer[] = { null, forrest, random };
    int whichOption = 1;
    int id = 0;
    char action = ' ';
    char accSrc = ' ';
    char accDest = ' ';
    double amount = 0;
    BankAccount src = null;
    do {

      try{
        // process JOptionPane input information
        String input = JOptionPane
            .showInputDialog("Please enter your transaction information: ");
        Scanner s = new Scanner(input);
        id = Integer.parseInt(s.next());
        action = Character.toUpperCase((s.next().charAt(0)));

        if (action == 'T') {
          amount = s.nextDouble();
          accSrc = s.next().charAt(0);
          accDest = s.next().charAt(0);
        } else if (action == 'G' || action == 'I') {
          accSrc = s.next().charAt(0);
        } else {
          // if D,W
          amount = s.nextDouble();
          accSrc = s.next().charAt(0);
        }

      } catch (IOException e){

      }
      // taking action accordingly (T)ransfer, (D)eposit, (W)ithdraw, (I)nterest
      if (action == 'T') {

        (customer[id].getAccount(accSrc)).transfer(amount,
            customer[id].getAccount(accDest));
      } else if (action == 'G') {
        System.out.println("The current balance on your " + accSrc
            + " account is "
            + customer[id].getAccount(accSrc).getBalance() + "\n");
      } else if (action == 'D') {
        (customer[id].getAccount(accSrc)).deposit(amount);
      } else if (action == 'W') {
        (customer[id].getAccount(accSrc)).withdraw(amount);
      } else if (action == 'I') {
        (customer[id].getAccount(accSrc)).computeInterest();
      }
      whichOption = JOptionPane
          .showConfirmDialog(null , "Do you want to continue?");

      System.out.println("The balance on " + customer[id].getName()
          + " auto account is " + customer[id].A.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " savings account is " + customer[id].S.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " checkings account is " + customer[id].C.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " loan account is " + customer[id].L.balance + "\n");

    } while (whichOption == 0);

  }
}

Answer 1

这是因为你在try/catch执行的操作都没有抛出IOException。

根据Scanner javadoc

大多数Scanner类方法抛出FileNotFoundException （由于不从文件中读取，因此不适用于您的情况）（或） IllegalArgumentException （或） IllegalStateException

您需要将IOException更改为上述任一异常（或）删除try / catch。

Answer 2

您可以删除IOException和try catch，因为try catch中的所有语句都不会抛出此异常

Answer 3

在try块中抛出IOException似乎没什么

Answer 4

在try块中没有方法调用抛出IOException ，这就是catch是无法访问的代码的原因。

您可以安全地删除try和catch，因为这种情况永远不会发生。

Answer 5

你的catch块是空的，表明你无论如何都不会真正处理异常。 你可能在那里有一些代码让你抓住它，但现在你已经没有它了。 只需删除整个周围的try-catch ，就不会有其他问题。

Answer 6

try/catch块为空，代码不会抛出IOException但它可能抛出其他异常。